Battery and resistance calculations

[mnealtx]

Looks like the trustfires hold up best for the type of usage we'd put them through - thanks for the info.

[aff-tar]

Great job! Thank you!

[Koman]

Good job bros.

[styl3r]

you could instal a diode on the battery out so no voltage/ current can pass back to the battery
cheers
styl3r

[jgonz17]

Informative

[Krism]

The current is determined by the voltage and the resistance ie I=V/R so I don't see how you can control both as one determines the other. (assuming the resitance is fixed, basically the atomiser resistance is more or less fixed).


So assuming the resistance is 2 ohms, then if you set the voltage to 4v then it would seem you are defining the current I=V/R = 4/2 as 2 amps.

The only way you are going to get 1 amp though a 2 ohm resistor I=V/R
1=V/2 thus V=2 so you are saying the voltage is 2, so I don't see how you can fix both at the same time.

You are correct unless you have a device like the eVic that limits current at 11 watts so technically you could have 11 watts at 1 ohm of resistance and run it at several different voltages. Although it doesn't change anything 11 watts at 3.5 v is the same as 11 watts at 5v. The Wattage is what produces more heat not the voltage.