Selecting the correct juice density.

[Al Bundy]

Puff counts vary a lot and are probably the least accurate way to calculate nicotine intake.

http://www.e-cigarette-forum.com/for...fs-per-ml.html

Can someone help me with the math...???

Nicotine safety

If you don't like the "puffs", how many ml are equivalent to an analog? That's what the end equation assumes because x/puff * puff//y = x/y (corrected).

I still don't see how you can claim it's the least accurate way to determine nicotine intake as the method does produce estimates, the question of intake would directly relate to the absorption efficiencies.

BTW, there appears to be minor error in the graph (plasma in nicotine s/b nicotine in plasma).

[Al Bundy]

Until someone comes up with an accurate value for how much of the nicotine is lost during vaporization, how much is lost in the air flow during intake and outtake and ultimately how much is absorbed into the blood stream during the whole process, the equations are pretty damn silly. Jaaxx posted a simple method that is about as accurate as you're going to get until real data is available.

Start low..raise until you feel your need satisfied. Always use the lowest possible dosage to satisfy your addiction.

How much nicotine is lost doesn't matter. The density of the liquid is uniform, so regardless if you have small cloud of vapor or a thunderhead worth of vapor, the vapor should contain equivalent densities.

As to Jaxx's equation, the math simply doesn't work. You can't solve a problem with one equation and two unknowns. He's just guessing at one of the unknowns which completely defeats the purpose to begin with. There is no "accuracy" in the problem because it can't be solved without "guessing".

[Al Bundy]

I'm not sure where this graph came from, but where does vapor fit into the graph? Is it closer to the spray, inhaler, or cigarette?

[Kate]

What we know:

The average amount of eliquid use per day is 2ml.
Manufacturers claim 300 puffs per ml, most users count less than 60.
Nicotine in eliquid is measured in mg per ml.
The machine puff count for an average cigarette suggests that 1mg is delivered.
There might be around 20 drops per ml/0.05ml per drop.

If these statements are accurate then 2x drops of 10mg eliquid = 1 cigarette
2ml of 10mg eliquid = 20 cigarettes

If you follow the conversation on the thread you'll see that the graph wasn't posted in response to your calculations. It makes a different point about steady doses or spikes. There are no scientific studies about vapour yet so we don't know how it's absorbed or how effective it is.

[Al Bundy]

What we know:

The average amount of eliquid use per day is 2ml.
Manufacturers claim 300 puffs per ml, most users count less than 60.
Nicotine in eliquid is measured in mg per ml.
The machine puff count for an average cigarette suggests that 1mg is delivered.
There might be around 20 drops per ml/0.05ml per drop.

If these statements are accurate then 2x drops of 10mg eliquid = 1 cigarette
2ml of 10mg eliquid = 20 cigarettes

If you follow the conversation on the thread you'll see that the graph wasn't posted in response to your calculations. It makes a different point about steady doses or spikes. There are no scientific studies about vapour yet so we don't know how it's absorbed or how effective it is.

This is the study I've found determining the actual delivered (yield*) nicotine, it's not 1mg / cig because it varies dependent on brand:

Erowid Tobacco Vault : Info on Nicotine Content of Cigarette Brands

The 2 ml is the same estimate I'm using, .1ml / cig * 20 cig = 2ml. The problem I was discussing was the density of the liquid on face value is much higher than analogs which is cause for concern.

As I pointed out, assuming comparable absorption rates, then 36 mg density for the same number of "puffs" would be equivalent to smoking FIVE cigarettes at once worth of nicotine. However, if you're using 7mg density juice, then the e-cig in terms of nicotine will deliver approximately the same amount as the analog.

BTW, I'm using the linear mode rather than the threaded.

[Kate]

That sounds about right per measure if your stinkies are 0.7mg. Forget about accurate measurements for puffs though, there is so much variation and too many variables to make it a reliable marker.

Nicotine safety

[Al Bundy]

That sounds about right per measure if your stinkies are 0.7mg. Forget about accurate measurements for puffs though, there is so much variation and too many variables to make it a reliable marker.

Nicotine safety

Statistically, on average, I think "puffs" can be a reliable marker. Of course it varies, but the statistical methods would account for the variation.

If you had a 100 people smoking and average the number the number of "puffs" per cig across the 100 people, then an estimate for the population mean number of puffs exists. This is the Central Limit Theorem. They don't have to puff equally, the "average" would still exist. Same deal for vaping, regardless of the variation between people.

This is basic statistical theory.

Oh and you could determine a confidence interval about the estimate that would account for whatever percentage you'd like, 90%, 95%, 99%.

[surbitonPete]

I think someone has been watching too much of that FBI program.....Numbers! lmao

[Kate]

Here you are, puff statistics, the best you're going to find in real life - http://www.e-cigarette-forum.com/for...fs-per-ml.html

That says that per puff vaping 10mg eliquid is at least twice as potent as a puff on a 1mg cig.

Do you think that means we are vaping twice as much nicotine as we smoked?

[Al Bundy]

Here you are, puff statistics, the best you're going to find in real life - http://www.e-cigarette-forum.com/for...fs-per-ml.html

That says that per puff vaping 10mg eliquid is at least twice as potent as a puff on a 1mg cig.

Do you think that means we are vaping twice as much nicotine as we smoked?

Well, the poll has some statistical bias because it doesn't account for variances in equipment. But yes, it's about the only data that I've seen so it's the only thing we can go on.

As for your question, using my rough equation the 10 mg juice would be the equivalent of a 1.0 mg analog, so no. I pointed this out earlier in the thread.

However if you're smoking a 1.0 mg analog and using 36 mg juice to vape, then you're vaping an 3.6 mg analog equivalent which is 3.6 times as potent.