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  1. #11
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    I'm eager to try the 5v setup on my Grand as well. Just ordered a couple of them from Randy @rtdvapor!
    I've tried the dual coils on another 5v pv and I loved it so I hope it does the same for my Grands.

    Right now, I'm loving Boge 2ohm cartos and dual coil cartos on my Grands. Can't seem to get the hand of atties.

  2. #12
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    I run the 5v all the time as well, try it with a good 2ohm Atty its a super vape !
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    This is very interesting.Im looking at a purple Grand.I need 5v and this will work.

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    Quote Originally Posted by wigglr View Post
    so Landlord (I'm pretty ignorant/dumb when it comes to electrics/wiring/V/W....) the bottom picture shows a 4.6 -- does that mean when you are hitting it you are only getting 4.6V out of the battery, not 5?

    So when calculating watts, I should plug in 4.6 - 4.8 instead of 5 in order to decide what resistance atomizer I want to achieve those watts? I like a hotter hit -- so if I am using that battery it looks like I should go lower in ohms than I thought (I put 5 into the watts calculator)
    The wattage produced is more or less a measurement of power or heat. The resistance to the applied voltage creates the wattage.
    So, the more voltage applied, OR the lower the resistance to the voltage the more wattage produced, thus more heat...

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    Thanks, Mike but I think I have that part down (FINALLY!)
    My real question (I am terrible at getting those across) was:
    is the output of the battery actuallllly ~4.6(at least for the battery in the picture) and NOT 5V. Because I am looking at that battery and trying to decide what atomizer to use. When using the ohms law calculator, I keep putting in 5(V) into the calculator and my desired wattage in order to know what resistance atomizer I should buy. However, would I be "misled" by presuming that the total watts would be a product of 5(V)? as it seems the V I should input into the calculator is actually something like 4.6-4.8 and then decide what atomizer I should get using my desired wattage and 4.6-4.8 insteaad of 5


    AND BREATHE
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    Quote Originally Posted by wigglr View Post
    Thanks, Mike but I think I have that part down (FINALLY!)
    My real question (I am terrible at getting those across) was:
    is the output of the battery actuallllly ~4.6(at least for the battery in the picture) and NOT 5V. Because I am looking at that battery and trying to decide what atomizer to use. When using the ohms law calculator, I keep putting in 5(V) into the calculator and my desired wattage in order to know what resistance atomizer I should buy. However, would I be "misled" by presuming that the total watts would be a product of 5(V)? as it seems the V I should input into the calculator is actually something like 4.6-4.8 and then decide what atomizer I should get using my desired wattage and 4.6-4.8 insteaad of 5


    AND BREATHE
    What your seeing is known as the voltage drop caused by the resistance of the atty. The wattage produced is a direct result of the applied voltage, not the under load reading that shows the voltage drop. In order to get a specific wattage out, you must use the correct applied voltage in the ohms law calculator. Not what it is after the resistance of the atomiser reduces it. Understand?
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    Mike. Thanks for sticking this one out with me HAHA

    Now I believe I understand... I should NOT use the V depicted in the bottom picture of his that shows the 4.6 (the voltage drop picture) in the ohms calculator
    However, the batteries themselves say 4.8 - so should I use 4.8 or 5? (Not really sure how big of a difference that makes, though)

    Once again, Mike you're awesome

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    Quote Originally Posted by wigglr View Post
    Mike. Thanks for sticking this one out with me HAHA

    Now I believe I understand... I should NOT use the V depicted in the bottom picture of his that shows the 4.6 (the voltage drop picture) in the ohms calculator
    However, the batteries themselves say 4.8 - so should I use 4.8 or 5? (Not really sure how big of a difference that makes, though)

    Once again, Mike you're awesome
    Many Many years of electronics school and hands on Electronics Technician at a couple of companies..anyhow. Here's the info you need to use. The REAL accurate, actual voltage of your batts fresh off the charger, and the real measurement of the attys your using. Do you have a digital multimeter?

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    As of right now, I don't -- but I am researching prices so I can buy one with my paycheck on Friday. I went to buy one this weekend at Home Depot and Lowes -- cheapest I saw was $20 .... RTD had one for 9
    Any suggestions?

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  10. #20
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    Wait so if I am using 18650s... I should use that number that can be like 4.xx (ex: 4.19) and NOT 3.7 like I have been doing?

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