Protege review by TGWTF

[anim8r]

Just ordered mine tonight.

[crashtestjeep]

I totally did the dance wrong, Im an idiot! I went for the actual touchdown dance! Ooops, lol! :blush:

[Moobyghost]

There is a touchdown dance?

[seminolewind]

Any 3.7 volt battery produces the same amount of vapor. However, the bigger the battery, the longer the bat stays at peak output. And, the smaller bats start with a fairly short peak time, and then as the bat gets older, the peak seems to last a shorter and shorter time.
My 14500 gives me peak performance for hours, like 5-6 hours. My 901 bat, more like an hour before dropping off. Sheesh, I need another mod, the 901 bats are not worth charging to me.

[ted26]

Originally Posted by markarich159

It's actually the current(amperage) of the higher rated batteries that make them perform better. Every battery has what's called a C rating(discharge rating). Most Li-ion batteries are rated between 1C and 2C. Multiply the C rating by the total capacity of the battery to get that battery's maximum discharge rate(or the highest current the battery can provide at any one time). Higher capacity batteries mean they can discharge a higher current. Since power is current times voltage, a higher current provides more power at the same voltage.

I am not sure this is true as volts=amps x resistance and therefore amps=volts / resistance....volts and resistance are both the same as with a smaller battery so should give exactly the same ampage but last longer!

[markarich159]

Originally Posted by ted26

I am not sure this is true as volts=amps x resistance and therefore amps=volts / resistance....volts and resistance are both the same as with a smaller battery so should give exactly the same ampage but last longer!

Your referring to ohms law and ohms law has to do with circuits not batteries. Ohms law states the voltage drop over a circuit is equal to the circuits resistance multiplied by the current. The resistance of the circuit is always the same(as long as the circuit elements don't change) the current depends on the voltage drop applied over the circuit. The larger the voltage the greater the current that can be pushed thru the circuit's resistance.

Batteries are EMF piles that generate a voltage and current by using a the chemical energy of a redux(reduction/oxidation reaction). By oxidizing one metal at the positive end(the anode) and reducing another metal/substance at the negative end(the cathode) the batterties create a voltage potential. The Batteries total Voltage depends upon the relative oxidation/reduction potentials of the respective metals involved as well as the concentrations of the ionic solutions the metals are associated with. The batteries total current(amperage) depends on the quantity of the metals involved.

The maximum discharge rate of a battery is a function of the battery's total available charge(in mAh) multiplied by it's maximum discharge rate(measured in C). So, for example a 3.7V 2400mAh battery with a C rating of 1 can provide an average voltage of 3.7V with a maximum discharge current of 2.4Amps for 1 hour) 2400mAh*1C= 2400mA or 2.4 amps for 1hour. The higher the C rating the higher the maximum discharge current, but the shorter amopunt of time that current can be maintained.

Lets contrast this with a standard Joye 510 battery with a 180mAh rating at 1C. 180mAh*1C= 180mA or .18A for 1 hour. That's a much , much lower possible maximum current that the Joye battery can provide as compared to the 18650 3.7V 2400mAh battery.

Seeing that the Joye 510 atomizer has a resistance of about 2.4ohms and operates at 3.7V, using ohms law it would run optimally at Current=voltage/resistance:::Current=3.7V/2.4ohms= 1.5Amps. Since the JOye 510 battery can only provide a maximum of 0.18Amps at 1C, the atty will be underpowered. The 18650 battery can provide 2.4Amps, so the atty will have all the current it needs(plus more, which it won't use according to ohms law) to run at optimal power.

This is why higher rated batteries outperform lower rated batteries.

[tparganos]

Originally Posted by navyboym

I have a Prodigy, at 5V, were i like the vapor and all, dripping all the time kinda gets to be a pain sometimes, plus it likes to melt carts. I'm thinking about cutting my carts back to correct that problem. So I'm thinking the 3.7V option might be the way to go so that I don't have to drip ALL the time.

If you use this without the resistor and the 18650 batteries you will be at 3.7v and they last all day.

[redrhino]

Just ordered mine tonight 2