So there was a cell study published recently that took human and rat lung cells and exposed them to both cigarette smoke and e-cig vapor (with and without nicotine). Dr. Farsilinos responded saying that the study was bogus based on a detail he saw in one of the charts.
What happened is they were measuring the nicotine in molarity and not in milliliters. For those of you unfamiliar, 1M = 1 molar of solute in 1 liter of a solution. So, essentially 1 molar (1M) = 1 mol/L.
Dr F. concluded that they were using concentrations of nicotine that would never been seen in real life conditions (see the link above where he explains).
Dr. F's detraction resulted from a chart that listed the following concentrations of nicotine they applied to the cells. They were:
.1 mM
.5 mM
2.5 mM
5 mM
10 mM
(A mM = millimole or 1/1000th of a mole).
Now, the molar mass of nicotine is 162.23g/mol. This means that 1M of nicotine = 162.23g. Since 1M = 1mol/liter, this means that there would be 162.23g of nicotine in one liter of their solution.
Now here's where I am wondering if Dr. F messed up his calculation. A millimole = .001 M. Thus a millimole of nicotine = .16223g (let's round to .16g). That would be .16g/L.
Now .1 mM of nicotine = 160g x 0.0001 = .016g/L. And so on for the rest of the chart presented in the paper. Here would be the conversions in grams per liter:
.5 = .08g/L
2.5 = .4g/L
5 = .8g/L
10 = 1.6g/L
Now, you are probably thinking, "Yes, but you have grams per liter. We need milligrams per milliliter. Therefore, you would need to move the decimal three places to the right. Hence, .016g/L would equal 16mg/mL. Right?"
Wrong. 0.016g/L = 0.016mg/mL. It's the same. It's something we learn in elementary school called cancellation.
The density of pure nicotine is 1.01g/cm^3. This equates 1:1 with mg/mL. Thus, the density of pure nicotine (undiluted) would be 1.01g/mL or 1010mg/mL.
Dr. F, is claiming that 10 mM =1600mg/mL. This is impossible as that is more nicotine than is possible to fit into one mL, even if it was pure and undiluted. (As I said above, pure nicotine is 1010mg/mL).
I conclude that Dr. F. is wrong when he says they were using 16mg/mL, 80mg/mL, 400mg/mL, 800mg/mL, and especially 1600mg/mL (impossible), etc. He moved the decimal place over when he shouldn't have. Or perhaps I am completely wrong and talking out my behind (I am not a chemist and admit I could be totally confused about molarity and the densities and masses of the chemicals here).
I know we have chemists here. I would like it if an expert would show me the error of my ways, which I fully admit is possible. Again, I am no expert. I'm just a guy who thought that surely these researchers cannot be so silly as to use outrageous amounts of nicotine such as 1600mg/mL!
What happened is they were measuring the nicotine in molarity and not in milliliters. For those of you unfamiliar, 1M = 1 molar of solute in 1 liter of a solution. So, essentially 1 molar (1M) = 1 mol/L.
Dr F. concluded that they were using concentrations of nicotine that would never been seen in real life conditions (see the link above where he explains).
Dr. F's detraction resulted from a chart that listed the following concentrations of nicotine they applied to the cells. They were:
.1 mM
.5 mM
2.5 mM
5 mM
10 mM
(A mM = millimole or 1/1000th of a mole).
Now, the molar mass of nicotine is 162.23g/mol. This means that 1M of nicotine = 162.23g. Since 1M = 1mol/liter, this means that there would be 162.23g of nicotine in one liter of their solution.
Now here's where I am wondering if Dr. F messed up his calculation. A millimole = .001 M. Thus a millimole of nicotine = .16223g (let's round to .16g). That would be .16g/L.
Now .1 mM of nicotine = 160g x 0.0001 = .016g/L. And so on for the rest of the chart presented in the paper. Here would be the conversions in grams per liter:
.5 = .08g/L
2.5 = .4g/L
5 = .8g/L
10 = 1.6g/L
Now, you are probably thinking, "Yes, but you have grams per liter. We need milligrams per milliliter. Therefore, you would need to move the decimal three places to the right. Hence, .016g/L would equal 16mg/mL. Right?"
Wrong. 0.016g/L = 0.016mg/mL. It's the same. It's something we learn in elementary school called cancellation.
The density of pure nicotine is 1.01g/cm^3. This equates 1:1 with mg/mL. Thus, the density of pure nicotine (undiluted) would be 1.01g/mL or 1010mg/mL.
Dr. F, is claiming that 10 mM =1600mg/mL. This is impossible as that is more nicotine than is possible to fit into one mL, even if it was pure and undiluted. (As I said above, pure nicotine is 1010mg/mL).
I conclude that Dr. F. is wrong when he says they were using 16mg/mL, 80mg/mL, 400mg/mL, 800mg/mL, and especially 1600mg/mL (impossible), etc. He moved the decimal place over when he shouldn't have. Or perhaps I am completely wrong and talking out my behind (I am not a chemist and admit I could be totally confused about molarity and the densities and masses of the chemicals here).
I know we have chemists here. I would like it if an expert would show me the error of my ways, which I fully admit is possible. Again, I am no expert. I'm just a guy who thought that surely these researchers cannot be so silly as to use outrageous amounts of nicotine such as 1600mg/mL!