% of e-liquid vaporized by higher heat

[trying]

Many vapors like to increase the power of their mod to increase the heat used to vaporize e-liquid which in turn increases the % of liquid vaporized. I am having difficulty finding the percentages of e-liquid which is not vaporized on an average mod per puff, if there is such a thing.
Does anyone know the answer and if possible the ratio of increased power to increased % of liquid vaporized ?

 

[somdcomputerguy]

I would certainly like to know this too. I'm almost definitely sure it would would require time, money, equipment, and one's own personal vaporizer to get an accurate measurement. All I know for sure is that it is not 100%, and probably more than 50%.
Southern Maryland Computerguy - Vape

 

[Alien Traveler]

Many vapors like to increase the power of their Mod to increase the heat used to vaporize E-liquid which in turn increases the % of liquid vaporized. I am having difficulty finding the percentages of E-liquid which is not vaporized on an average mod per puff, if there is such a thing.
Does anyone know the answer and if possible the ratio of increased power to increased % of liquid vaporized ?

I do not understand why you want "%". Percent of what? Of the liquid volume in a tank?

 

[trying]

Each puff a given amount of liquid is released from the tank to the atomizer.
The percentage of that dose is what I am after or just a general range 70% , 80 % ?

 

[Hans Wermhat]

Unless you use a nuclear clock to precisely time each puff and have some kind of super power that allows you to take the exact same duration and volume per puff, there is no exact answer to your question. Too many variables.

 

[dhood]

The liquid isn't "released from the tank to the atomizer". The wick absorbs the juice. As the atomizer heats up and the juice is boiled, more juice is absorbed. The sucking action helps to pull the liquid into the juice channels and the swap of air you see in a tank maintains the vacuum. So there is no set amount of liquid that is boiled each time you press the button. There is no way to determine the percentage that isn't vaporized because whatever is in the wick that doesn't get boiled is still there ready for the next puff.

 

[edyle]

Many vapors like to increase the power of their Mod to increase the heat used to vaporize E-liquid which in turn increases the % of liquid vaporized. I am having difficulty finding the percentages of E-liquid which is not vaporized on an average mod per puff, if there is such a thing.
Does anyone know the answer and if possible the ratio of increased power to increased % of liquid vaporized ?

If you double the wattage, you double the amount of eliquid vaporized per second.

 

[Mad Scientist]

Many vapors like to increase the power of their Mod to increase the heat used to vaporize E-liquid which in turn increases the % of liquid vaporized. I am having difficulty finding the percentages of E-liquid which is not vaporized on an average mod per puff, if there is such a thing.
Does anyone know the answer and if possible the ratio of increased power to increased % of liquid vaporized ?

I'm not really clear on what you are asking (I'm a little hung over and it's early lol). What is the ultimate information you are after and maybe someone will know the answer.

Increasing heat (meaning increasing total power applied) will increase the volume of liquid boiled and vaporized. The relationship is not simple. As an example : http://www4.ncsu.edu/~doster/NE402/Text/BoilingHeatTransfer/BoilingHeatTransfer.pdf

 

[Bunnykiller]

obviously its 100% if it doesnt spit/pop.... the coil only vaporizes what it vaporizes.... basically saying you drink 100% of what you swallow...

 

[Alien Traveler]

obviously its 100% if it doesnt spit/pop.... the coil only vaporizes what it vaporizes.... basically saying you drink 100% of what you swallow...

If we want to be somewhat technical we may say that part of produced by coil vapor will condense on chamber walls and chimney; so efficiency is not really 100%.

 

[Mad Scientist]

If we want to be somewhat technical we may say that part of produced by coil vapor will condense on chamber walls and chimney; so efficiency is not really 100%.

Yes but the vapor will give up heat to the chamber walls in order to condense and that heat will cause additional evaporation of some of the liquid on the chamber walls so ... lol.

 

[Alien Traveler]

Yes but the vapor will give up heat to the chamber walls in order to condense and that heat will cause additional evaporation of some of the liquid on the chamber walls so ... lol.

Yes, but still not 100%.

 

[trying]

Bottom line more vapor per puff equals more nicotine per puff.
or a lower powered mod with 24mg liquid would roughly deliver an amount of nicotine per puff
equal 16mg liquid when vaporized by a higher powered mod.

 

[Alien Traveler]

Bottom line more vapor per puff equals more nicotine per puff.
or a lower powered mod with 24mg liquid would roughly deliver an amount of nicotine per puff
equal 16mg liquid when vaporized by a higher powered mod.

3 ml a day at 24 mg are equal to 24 ml a day at 3 mg.

 

[WattWick]

Not to stir things up... but you could run 10 watts through a coat hanger and not get enough heat to vaporize any liquid. You could double the wattage and get the exact same result - not enough heat to vaporize any liquid.

As for percentages. Even tho the tank is a tank, it acts more like a roll of toilet paper. You start at one end and use whatever's there until it's all gone. You don't dispense "dosages" which are either fully or partially spent.

 

[93gc40]

Is going to take an advanced degree and lots of labs tech to answer the question, based on AT the ATTY.. Why not just calculate your consumption and dosage based on amount of Juice consumed.. Using basic math, divide juice by puffs, hours or days, to get dosages.