Firing mod at lower ohms than rated

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An0maly

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Dec 16, 2016
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Hello,
I got a subox mini c, which is rated to fire down to 0.3 ohms. Today i bought the rta for the joytech ultimo and some clapton wire. After I installed my first coil i realizied that it was only 0.15 ohm, but I still tried to fire it and it worked. I also did the Ohms Law math and the ampere wasn't even close to 20. (around 10)
So is it safe to fire a 0.3 ohm rated mod at lower ohms?
 
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smacksy

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Aug 17, 2014
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It isn't. It's just the ohm I ended up with the wire i bought. And I don't see a reason to buy a different wire, if it's safe to use it. Since everything worked perfectly so far I'm just gona stick with this build
Ohms are determined by how many wraps for your coil (resistance) with any wire....

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NU_FTW

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Dec 6, 2016
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you are doing your math incorrectly to determine your amp draw. in a regulated mod you divide the Watts by sum of the batteries min voltage 3-3.1 per battery. Not by the volts your mod says it is firing coil at. So in a single battery config you divide 40 (watts) by 3 (min voltage of single cell). For total amp draw of 13.33. If it is dual 18650 you add the two min voltage together so 3 + 3 =6 divide 40 by 6 and you get a 6.66 amp draw
 
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David Wolf

Moved On
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Dec 11, 2014
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Charlotte, NC
Hello,
I got a subox mini c, which is rated to fire down to 0.3 ohms. Today i bought the RTA for the joytech ultimo and some clapton wire. After I installed my first coil i realizied that it was only 0.15 ohm, but I still tried to fire it and it worked. I also did the Ohms Law math and the ampere wasn't even close to 20. (around 10)
So is it safe to fire a 0.3 ohm rated mod at lower ohms?
My recommendation is to never operate a mod outside of the manufacturers specifications, they're there for a reason. The specs have a margin of safety built in for the design and you're going beyond that.
 

Layzee Vaper

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Apr 27, 2015
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you are doing your math incorrectly to determine your amp draw. in a regulated mod you divide the Watts by sum of the batteries min voltage 3-3.1 per battery. Not by the volts your mod says it is firing coil at. So in a single battery config you divide 40 (watts) by 3 (min voltage of single cell). For total amp draw of 13.33. If it is dual 18650 you add the two min voltage together so 3 + 3 =6 divide 40 by 6 and you get a 6.66 amp draw

Please be careful, using the above equation is incorrect. You have to account for the efficiency of the Mod.


You need to know:
The power output
The efficiency of the chipset. (usually between 80% and 95%)
The mods low battery cut off point (usually around 3 volts)
The CDR of the battery. ( I use mooches results rather than manufacturer spec as these are often inflated)

This information should be within the specifications or the instructions that came with the mod.

If you put the above information into the battery drain calculator on steam engine (Battery drain) It will tell you how much current is being drawn from the battery. Make sure that the maximum current draw is below the tested CDR of the battery.

My recommendation is to never operate a mod outside of the manufacturers specifications, they're there for a reason. The specs have a margin of safety built in for the design and you're going beyond that.

Yep, and there is simply no advantage to building very low resistance coils on a regulated mod. In fact a higher resistance coil with more wraps and more surface area makes much more sense.
 

KenD

Vaping Master
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Aug 20, 2013
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kennetgranholm.com
Ohms are determined by how many wraps for your coil (resistance) with any wire....

Sent from my XT1585 using Tapatalk
The length and gauge of the wire actually. A 10cm piece of 28ga ss316 wire will have the same resistance whether it's six wraps with a 4 mm id or 11 wraps with a 2 mm id.

Sent from my K6000 Pro using Tapatalk
 

smacksy

Ultra Member
ECF Veteran
Aug 17, 2014
2,330
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Alexandria, Louisiana USA
The length and gauge of the wire actually. A 10cm piece of 28ga ss316 wire will have the same resistance whether it's six wraps with a 4 mm id or 11 wraps with a 2 mm id.

Sent from my K6000 Pro using Tapatalk
You're right Ken, thx

Sent from my XT1585 using Tapatalk
 

Sludge Van Diesel

Super Member
ECF Veteran
Sep 24, 2009
832
683
Barnet UK
I'm having a similar dilemma although with shop bought attys.

I've got an e-pipe that has been discontinued & I'm running out of attys. I've found some that on first appearance are the same shape & size, although my original attys are 2.4Ω & the new ones are 1.8Ω.

The batteries in both my pipe & the device these are intended for are identical (18350, 3.7V, 800mAh).

Would I experience any issues?

I'm asking as in the 8 years or so I've been vaping, I've always used parts from the original manufacturer that are intended for the model I'm using (with the exception of when I was using M401 models), so I don't really know much about swapping parts.

Sorry to hijack the thread, I did post this question elsewhere, but I'm unsure if I posted in the right place (ECF has changed considerably since my last regular visits).
 

NU_FTW

Ultra Member
Dec 6, 2016
1,205
2,962
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Please be careful, using the above equation is incorrect. You have to account for the efficiency of the Mod.


You need to know:
The power output
The efficiency of the chipset. (usually between 80% and 95%)
The mods low battery cut off point (usually around 3 volts)
The CDR of the battery. ( I use mooches results rather than manufacturer spec as these are often inflated)

This information should be within the specifications or the instructions that came with the mod.

If you put the above information into the battery drain calculator on steam engine (Battery drain) It will tell you how much current is being drawn from the battery. Make sure that the maximum current draw is below the tested CDR of the battery.



Yep, and there is simply no advantage to building very low resistance coils on a regulated mod. In fact a higher resistance coil with more wraps and more surface area makes much more sense.

no not incorrect. Maybe incomplete. Tell u what throw on multiply resulting amps by 1.2 to account for worry of 80% efficiency and voila close enough
 
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