Technonut asked me to put this here, so here I am
As we all know usage of mechanical mods is connected with
voltage drops. They are caused mainly by electrical construction of mod but also by the internal resistance of the battery.
So I decided to check how the internal resistance of different batteries affect on voltage drops.
The test was carried out by use of
model atomizer with 1ohm resistor:
For each battery voltage was measured by use of multimeter 2 times:
first directly on battery,
then the battery was inserted into the mod and measurement was taken on atomizer pins.
In the game participated:
From left:
* AW IMR 18350 used for about half year, 50-60 charging cycles,
* Efest v2 18350 - used for about half year, 50-60 charging cycles
* Noname 18350 - used for more than half a year, 50 charging cycles.
* AW IMR 18500 bought a second-hand, dont know history,
* Efest v2 18500 used for about 3-4 months, 30-40 charging cycles,
* Panasonic CGR 18500 - used for about 3-4 months, about 20 charging cycles,
* AW IMR 18650 - used for about 4 months, about 10 charging cycles,
* Samsung INR18650 (for laptop) - used for about 3-4 months, about 10 charging cycles,
* UltraFire XSL - used for about 4 months, about 10 charging cycles.
Model atomizer was powered by
69 mod which has quite small voltage drops.
Of course all the batteries were fully charged before the test.
And there are results:
So... now I'll do pretty
risky assumption ... The best result was for AW IMR 18500 battery and was
3.95 V. Voltage measured dircetly on battery was
4.19 V so total voltage drop was
0.24 V. Let's ASSUME it splitted into:
* 0.14 V - voltage drop on mod+atomizer,
* 0.1 V - voltage drop on internal resistance of battery.
So, assuming the voltage drop on mod+atomizer
was still the same (0.14V) we can calculate voltage drop on each battery:
As you can see, it is worth to pay attention to what you put into a mod