Dual Coil Assistance

[Bshollow]

Just really starting to get my feet wet with dual coils, and I'm using an iClearS. I have the 1.8 dual coil, which means each coil is actually 3.6 ohms.

Can I set the voltage or wattage as if it were a single 3.6 with no fear of popping the coil? It seems to not really hit as I'd like it to setting it like its 1.8 ohms.

Edit: And I just realized I put this in the wrong forum.../facepalm

 

[ElectricalSocket]

I'm not an expert, but I would say treat it like a 1.8ohm coil. When I used clearos I would worry about heating up the rubber grommet too much and wouldn't set it much higher than 1v more than the ohms (i.e. 3-3.3v on a 1.8ohm coil).

What are you setting it at? I def wouldn't set it any higher than 4.8v. That's me though.

 

[Bshollow]

I was vaping at 8 watts, so around 3.8/3.9 volts, and it feels rather lackluster.

 

[ElectricalSocket]

I was vaping at 8 watts, so around 3.8/3.9 volts, and it feels rather lackluster.

Hrmm I dunno. You could get away with going a little higher without popping the coil. I wouldn't want to burn that grommet though.

Sorry I'm of no help and hope you figure something out.

Edit: You may have already seen this, but just so I don't feel completely useless...

 

[Bshollow]

Thanks for the assistance anyway!

I jumped up to 10 watts just to see. Didn't break anything but it didn't fix anything either. I'm thinking its the juice.

 

[Bunnykiller]

if you have 2 @ 3.6 in parallel that will = 1.8 total. you battery will "see" the load as a 1.8 ohm coil. But it will now take 2 times the power to get both coils to be the "same" temp as a single 1.8 ohm coil. Does your battery have enuf power to supply 2 coils?

kinda like filling 1 bucket with one hose, it fills in in X amount of time, now you have put a Y valve on the end of the hose and are trying to fill 2 buckets with the same flow of water used originally... this will take about 2 X longer to fill the buckets than before. To fix the fill time you need to double the flow rate ( amps, power) by increasing the pressure or increasing the flow ( add more volts or increase watts) if the battery just doesnt have the power (mAh) there will be little increase of flow...

 

[Myk]

Just really starting to get my feet wet with dual coils, and I'm using an iClearS. I have the 1.8 dual coil, which means each coil is actually 3.6 ohms.

Can I set the voltage or wattage as if it were a single 3.6 with no fear of popping the coil? It seems to not really hit as I'd like it to setting it like its 1.8 ohms.

Edit: And I just realized I put this in the wrong forum.../facepalm

Go with wattage. Take the wattage that you'd use for 1.8Ω and double it. IME that will be around where you like it.

As far as voltage, I don't really know. I've never used singles as high as I've used in duals. Looking at the wattage chart it might be as simple as use the same voltage you'd use as if you were using a single coil's ohms.

 

[Bshollow]

Go with wattage. Take the wattage that you'd use for 1.8Ω and double it. IME that will be around where you like it.

As far as voltage, I don't really know. I've never used singles as high as I've used in duals. Looking at the wattage chart it might be as simple as use the same voltage you'd use as if you were using a single coil's ohms.

This fixed it! Thanks!

 

[Bshollow]

if you have 2 @ 3.6 in parallel that will = 1.8 total. you battery will "see" the load as a 1.8 ohm coil. But it will now take 2 times the power to get both coils to be the "same" temp as a single 1.8 ohm coil. Does your battery have enuf power to supply 2 coils?

kinda like filling 1 bucket with one hose, it fills in in X amount of time, now you have put a Y valve on the end of the hose and are trying to fill 2 buckets with the same flow of water used originally... this will take about 2 X longer to fill the buckets than before. To fix the fill time you need to double the flow rate ( amps, power) by increasing the pressure or increasing the flow ( add more volts or increase watts) if the battery just doesnt have the power (mAh) there will be little increase of flow...

Great explanation! Thank you!