OHM law question

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bwh79

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What mod? In a regulated/variable wattage device, battery drain is dependent solely on the watts setting and battery voltage, and not dependent on atomizer resistance. This is because power in = power out, and the batteries only ever output a fixed voltage -- all of the ohm's law stuff is taken care of by the chipset, varying its own internal resistance in order to draw the required power from the battery to apply to the atomizer.

I don't know what batteries you're using, but AFAIK there's no such thing as a 35A continuous discharge battery, and "pulse" or "peak" discharge rates are ill-defined and essentially meaningless. What you likely have are 20A batteries and depending on how they are wired, the amp load might be shared between them or applied to each individually.

Depending on the setup, you might be looking at either 20 or 40 amps max discharge. Which means that at 3.2 volts (nearly fully drained) you can push 40*3.2=128 watts, max. Halve that, for a generous safety margin as the battery begins to age, and you're looking at 64 watts of power. I wouldn't push more than that if I were you, at least not without a thorough understanding of what is going on under the hood, so to speak.
 

nic_fix

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what happened to the 1440 watts from my 12v post? it turns out he does know what he is doing. I did not know he is a retired professor of electronic engineering at the university of Chicago. go figure he built that doorbell. id go with know your gear. however having something violently explode in ones face may not be a pleasant experience. my motto remains don't mess with things I do not fully understand. getting killed kind of sucks. I am very happy with .125 ohms at 36 watts on ni200 with 520f. that is even a lot but I was told by an expert my atty can handle it. battery gets warm but been doing it a year already. I am just afraid of insane amps. probably better safe than sorry too. as for know your gear I am running a 600 amp 3 phase grain pump on the farm it was professionally installed but it still scares me. if that fails possible kaboom.
 

VNeil

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what happened to the 1440 watts from my 12v post? it turns out he does know what he is doing. I did not know he is a retired professor of electronic engineering at the university of Chicago. go figure he built that doorbell. id go with know your gear. however having something violently explode in ones face may not be a pleasant experience. my motto remains don't mess with things I do not fully understand. getting killed kind of sucks. I am very happy with .125 ohms at 36 watts on ni200 with 520f. that is even a lot but I was told by an expert my atty can handle it. battery gets warm but been doing it a year already. I am just afraid of insane amps. probably better safe than sorry too. as for know your gear I am running a 600 amp 3 phase grain pump on the farm it was professionally installed but it still scares me. if that fails possible kaboom.
It's probably not a good idea to mix Temperature Controlled configs into a general discussion of how Ohm's Law applies to non-TC gear.
 

Cullin Kin

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Here is what you are really drawing:

UfUHyYIl.png
 

MattyTny

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Since you're working with a regulated device you have to know what your box is capable of doing separate from your batteries.

To get to your question you want to use the resistance of 0.3ohms and either the voltage variable or the wattage variable given by your box mod. Then you will get the an estimate of the amps or current being drawn. Resistance of 0.3 and a wattage of 65 gives 4.42 volts and about 15amps. Safe to use with a regulated box and good batteries.

It all depends on the chip specs in your device though, your box needs to be able to handle a decent amount of current while giving you a high wattage limit and high voltage limit. The Sigelei150 for example has specs saying it does 150w or 7.5v, whichever limit it hits first. If you build a resistance low enough you can reach the maximum wattage while staying within the voltage range, such as a 0.3. What device and what batteries are you using?
 

coilburner

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alright so im new to running a vw box mod and a RDA, I got a quick question. I got 2 35w batteries in my box, and running 0.3ohms, I punch this into a ohms law calculator and I get this


Voltage (V) 10.5

Current (I) 35

Resistance (R) 0.3
Power (P)
Watts (W) 367.5




so does this mean, the max I can turn it up to is 10.5 volts?
Whats a 35w battery? Maybe that's where all your calculations get screwed up. BTW, what mod are you using that goes up to 10.5 volts?
 

VNeil

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I want to throw out one more idea, that may be buried in the above but I thought should be stated more directly. It was pointed out that few 18650 batteries have a true continuous discharge rating above 20A. Battery makers, particularly relabelers, are famous for overstating specs (known as "lying" in any other context). If your battery is rated above 20A continuous then you want to investigate further, and it might be a Very Good Idea to assume 20A. That is just an aside to my main point.

A regulated mod is essentially a black box in between the battery(s) and coil. That black box converts voltages and current back and forth to achieve a continuous power as the battery voltage declines from about 4.1V to 3.2V or whatever voltage the device cuts off at. Lets assume 3.2V although some people remove their batteries at a higher voltage in an attempt to maximize the battery life. And your device may "die", indicating a flat battery, at some other voltage.

Ohm's Law says power (watts) = voltage * current

If you assume a conservative upper limit of 20A per battery, then the maximum power you can safely get from that battery = 3.2*20 = 64 watts. If you have a dual battery mod then the maximum is double that, or 128 watts. I'm assuming a 3.2V cutoff but you want to check your particular device to see where it cuts off.

In principle you can get up to 20 * 4.1 = 82 watts, but only with a freshly charged battery. We want to conservatively calculate worst case, which is the last puff you take before you remove the battery by choice or the device cuts off.

The above is a very conservative calculation of the maximum power you can draw before you start pushing envelopes. If you push enough you may get the picture I posted above (jk! but something slightly less bad could actually happen, like the battery venting or something similar, or just a very poor battery lifespan)

The actual voltage across the coils and the current that passes through the coils will likely be different because that black box is converting voltage and current. But the important point is that, assuming 100% efficiency of the converter, the current drawn from the battery will always be the power level selected in a VW device divided by the battery voltage.

Since voltage converters do not usually run at a full 100% efficiency then this assumption adds a liberal bias to things but I don't believe those efficiency numbers are widely available. This counteracts the idea that we don't actually run our batteries "continuously", which in principle means from a fully charged state to depletion at ~3.2V or whatever without a break.

If you choose to run your mod at greater than the continuous rating, you will probably live, if you don't exceed it too badly :). If you do this, you are now "pushing the envelope" and you are on your own because the results of that push, depending on how far you push, are way outside the scope of any general rules of thumb. But we can see clearly that the 367.5 watts calculated in the OP was quite pushing the envelope!
 
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edyle

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alright so im new to running a vw box mod and a RDA, I got a quick question. I got 2 35w batteries in my box, and running 0.3ohms, I punch this into a ohms law calculator and I get this


Voltage (V) 10.5

Current (I) 35

Resistance (R) 0.3
Power (P)
Watts (W) 367.5




so does this mean, the max I can turn it up to is 10.5 volts?

We can't see where you are getting your numbers from.


looks like maybe you put in the 0.3 ohms and 35 amps in the ohms law calculator.
 

edyle

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You can't get 10+V out of 2 batteries. I don't know of any true 35A batteries out there. What you are looking at is a pulse rating, not the CDR. What are you trying to do. 'Splain it to us, Lucy. Lol!

he said it was a vw mod but he didn't say which one.
 

crxess

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The MAX your Regulated Box Mod can handle is the numbers Spec'd for the design.
What Box is it?
The Box should have full safety features that will manage your Maximum safe output as well as your minimum ohm load and minimum Battery drain.

People love to jump right on Theory and neglect actual Design.
 

VNeil

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Lol! I've seen a battery melt down in person. It's purdy frickin scary and I'm a pyro. I could feel the heat off it from 10 feet away. It burned the concrete! Not an actual hole in it so to speak, but it left a mark that wouldn't warsh off.
I'm not taking anything away from Mech Mod users. At least those that know what they are doing. But something I learned 45 years ago... all electronic circuits that have a significant source of power should have fuses. Particularly when that circuit can turn into an incendiary device if it fails.

And now almost every day I seem to read a story from a newbie in the New Member section talking about the Mech Mod he came home with after visiting a vape shop for the first time. With about 2 minutes of training. And asking "What's the deal with those Ohms?". Scary stuff.

I have often thought about playing with a Mech Mod, just because I'm a more advanced user and in theory know more than I need to know about the basic theory of What Can Go Wrong. And I'm like everyone else, every now and then I like something new and different. But then I think about that missing fuse...

(If Reos were a good bit cheaper I might indulge... they at least have some semblance of a fuse that I assume works)
 
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