ohms and coils

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rusirius

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No, no formula for that... Ohm's/Joule's law determine how much wattage you get for a given voltage based on your resistance, but with a variable wattage device it does all the work for you... You just set it to the power you want. And just so you aren't confused, they are not able to be set independent. Since they are naturally tied to one another... When you adjust the wattage you are also adjusting the voltage and vice versa... Think of it like this... Let's say you added a control to your car where you could set the number of gallon's per hour that flowed into the injectors... But you still had a gas pedal... They both are going to do the same thing... it's just that one is a different way of doing it...

But the key to remember is this... The higher the wattage (or voltage if you're setting it that way) the more vapor you will get... However, if your particular setup (the coil or wicks or tank) can't feed juice into the coil fast enough for your set power, then you'll get a burnt taste and dry hits... So just as Susan said, start out at like 6 watts and take a few drags... Then bump to 7 watts and try again... It'll be easier to notice the difference if you increment in whole numbers... You'll notice the vapor get more dense each step up... If you notice it start to taste burnt, or getting dry or less dense then you know you've gone too far... You may find that you can run at 11 watts without a burnt taste but still prefer it backed down to 6 or 7... It's all your own preference and what you like...
 

Kaezziel

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The purpose of the variable voltage/wattage is so that the user can customize the settings to their own personal liking. Some people like a warmer vape, some a cooler one. Also, different juices taste better at different settings... just play with it, experiment, have fun and don't get so hung up on the details...

Good luck and happy vaping!
 

realsis

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Agreed with above post. Find your particular sweet spot with each new juice flavor. It's different for everyone! My particular sweet spot is usually between 15.7 all the way to 40 watts depending on what I'm vaping and the rba or rda I'm using. I can go higher in my wattage without burning because I do my own builds but on a factory coil, it can burn pretty fast so if that's what your using, start out low and gradually increase to your sweet spot. If it starts tasting burned back back down .Hope this helps.
 

realsis

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Here is some general guide lines☆☆Power (watts) is the intensity of the vape. 6-8 watts is the “sweet spot” for most vapers
Current (amps) is what can burn out atomizers. 1.5 – 2.0 amps is fine. 2.0+ amps is risky
The lower the resistance of your device, the faster it will drain the battery
The lower the resistance- The lower the volts you should use
The higher the resistance- The higher the volts you can use
If using VV a good rule of thumb is to add resistance plus 2 volts then adjust up or down
So, with a 1.8 oHm Atty plus 2 volts = 3.8 volt setting
For a 3.7 volt device use 1.8 oHm resistance
Hope this helps.
 
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rusirius

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yea so if i lower my ohms will the volts go up or down. its a set wattage mod at 8.5w

That's a trick question.. :) I'll give you a little more detail to chew on... Let's take a vv/vw mod out of the equation. Let's say you had a straight up mechanical mod... That means that you are simply hooking a battery straight up to the coil... Nothing else in between...

The "voltage" will never change.. No matter what you do... You can put a .15 ohm coil in there or a 2.5 ohm coil in there and your voltage will always remain the same (forgiving voltage drop, but we don't need to worry about that right now). Because the VOLTAGE is being supplied from the battery... and that will remain constant... (aside from it dropping as the battery loses it's charge).

However, in this scenario, what WILL change is the wattage or power (which is a function of the voltage and wattage)... The lower resistance coil will draw a LOT more current than the 2.5 ohm coil...

Here's a quick aside that might help when thinking about current versus voltage... Think of a water hose.... Electricity flows just like water... Electrons flow from the negative side of the battery to the positive side of the battery...

Voltage is the "Pressure" of those electrons... Like the pressure your water pump is supplying...

Current is the "Amount" of those electrons or flow rate... Like how much actual water is flowing...

Now let's say you have a giant tank of water with a pump attached to it that supplies a constant 30psi... You're trying to fill a 55 gallon barrel up with water...

If you hook up a 1/4" tube to your pump and put that in the barrel it's going to take a very long time to fill up... Because the 1/4" tube is "resisting" the flow a lot... So we can say that it has very low "current" or flow rate....

On the other hand, if you get a 6" PVC pipe and pipe it straight from the pump to your barrel, now what's going to happen? Your barrel is going to be filled in seconds. Because now your "current" is very high...

Wattage is a function of current and voltage... Multiplied together actually... Current x Voltage = Wattage And wattage is "Power"... It's how fast you're able to fill that barrel...

In your e-cig, the coil is providing the "resistance"... The less resistance, the more current... Your battery is supplying the voltage... (generally 3.7v) So your wattage is determined by current x 3.7v... If you halve the resistance of your coil, the current spikes up much higher, because your flow rate increases... but the 3.7v remains the same... just as your water pump always supplied 30psi no matter what...

Does that make sense?

Now let's talk about vv/vw devices... These devices can "adjust" the amount of voltage or current even though the "pump" (your battery) stays the same... I won't give go into big detail about this as it's a bit more complex, but think back to your water hose for a minute...

If you place a "cap" over the water hose that has a 3/8" hole in it... you're going to get a specific flow rate and pressure... What happens when you put your thumb over the end of a hose? Right... it shoots across the yard and sprays your s/o in the eye... So if we swap that cap for one with a much smaller hole... let's say a 1/8" hole... NOW we have a MUCH MUCH higher pressure.... and we're shooting your neighbor two doors down in the eye... But at what expense? Our flow rate or "current" has decreased substantially.... We can't fill up a bucket very fast, even though we've got a tremendous amount of pressure (voltage). On the other hand, if we remove the cap all together what happens? We have a much higher flow rate... The bucket fills up pretty quick... But what happened to our pressure? It's barely leaving the end of the hose...

So... and here's the REALLY important part in case the rest of this has bored you out of your skull...

If we have a battery that's capable of 3.7v at 30amps... We can INCREASE the voltage or "pressure" of our output say 9v instead... But now we are only capable of outputting 12.33 amps... On the other hand, if we wanted to crank out 60 amps we can do so... But ONLY at 1.85 volts...

We can trade voltage for current or current for voltage... Just as we can put our thumb over a garden hose... But we can never exceed what our "pump" is capable of in the first place...

When you have a vv/vw device, it does exactly this... When you set that you want 4.7 volts out of the battery across your 2 ohm coil it ramps up the voltage from 3.7 to 4.7... and draws 2.7amps from the battery... On the other hand, when you set your voltage down to 3 volts on your same 2 ohm coil, it scales the voltage down, now only drawing 1.5 amps... You just went from vaping at 11+ watts to about 4+ watts...

On the other hand, when you set the wattage you're doing the exact opposite... When you say you want to vape at 4.5 watts it checks the coil and sees that it's 2ohms and outputs 3 volts.... When you crank it up to 11 watts it cranks up the voltage to 4.7 volts...

If on the other hand you leave it set for 11 watts and instead install a new 1.5ohm coil, it's going to drop down to around 4 volts to give you the same 11 watt output...

Hope all that makes sense... I know I tend to ramble a bit but I try to be as clear as possible without going completely overboard!
 
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