yea so if i lower my ohms will the volts go up or down. its a set wattage mod at 8.5w
That's a trick question..

I'll give you a little more detail to chew on... Let's take a vv/vw mod out of the equation. Let's say you had a straight up mechanical mod... That means that you are simply hooking a battery straight up to the coil... Nothing else in between...
The "voltage" will never change.. No matter what you do... You can put a .15 ohm coil in there or a 2.5 ohm coil in there and your voltage will always remain the same (forgiving voltage drop, but we don't need to worry about that right now). Because the VOLTAGE is being supplied from the battery... and that will remain constant... (aside from it dropping as the battery loses it's charge).
However, in this scenario, what WILL change is the wattage or power (which is a function of the voltage and wattage)... The lower resistance coil will draw a LOT more current than the 2.5 ohm coil...
Here's a quick aside that might help when thinking about current versus voltage... Think of a water hose.... Electricity flows just like water... Electrons flow from the negative side of the battery to the positive side of the battery...
Voltage is the "Pressure" of those electrons... Like the pressure your water pump is supplying...
Current is the "Amount" of those electrons or flow rate... Like how much actual water is flowing...
Now let's say you have a giant tank of water with a pump attached to it that supplies a constant 30psi... You're trying to fill a 55 gallon barrel up with water...
If you hook up a 1/4" tube to your pump and put that in the barrel it's going to take a very long time to fill up... Because the 1/4" tube is "resisting" the flow a lot... So we can say that it has very low "current" or flow rate....
On the other hand, if you get a 6" PVC pipe and pipe it straight from the pump to your barrel, now what's going to happen? Your barrel is going to be filled in seconds. Because now your "current" is very high...
Wattage is a function of current and voltage... Multiplied together actually... Current x Voltage = Wattage And wattage is "Power"... It's how fast you're able to fill that barrel...
In your e-cig, the coil is providing the "resistance"... The less resistance, the more current... Your battery is supplying the voltage... (generally 3.7v) So your wattage is determined by current x 3.7v... If you halve the resistance of your coil, the current spikes up much higher, because your flow rate increases... but the 3.7v remains the same... just as your water pump always supplied 30psi no matter what...
Does that make sense?
Now let's talk about vv/vw devices... These devices can "adjust" the amount of voltage or current even though the "pump" (your battery) stays the same... I won't give go into big detail about this as it's a bit more complex, but think back to your water hose for a minute...
If you place a "cap" over the water hose that has a 3/8" hole in it... you're going to get a specific flow rate and pressure... What happens when you put your thumb over the end of a hose? Right... it shoots across the yard and sprays your s/o in the eye... So if we swap that cap for one with a much smaller hole... let's say a 1/8" hole... NOW we have a MUCH MUCH higher pressure.... and we're shooting your neighbor two doors down in the eye... But at what expense? Our flow rate or "current" has decreased substantially.... We can't fill up a bucket very fast, even though we've got a tremendous amount of pressure (voltage). On the other hand, if we remove the cap all together what happens? We have a much higher flow rate... The bucket fills up pretty quick... But what happened to our pressure? It's barely leaving the end of the hose...
So... and here's the REALLY important part in case the rest of this has bored you out of your skull...
If we have a battery that's capable of 3.7v at 30amps... We can INCREASE the voltage or "pressure" of our output say 9v instead... But now we are only capable of outputting 12.33 amps... On the other hand, if we wanted to crank out 60 amps we can do so... But ONLY at 1.85 volts...
We can trade voltage for current or current for voltage... Just as we can put our thumb over a garden hose... But we can never exceed what our "pump" is capable of in the first place...
When you have a vv/vw device, it does exactly this... When you set that you want 4.7 volts out of the battery across your 2 ohm coil it ramps up the voltage from 3.7 to 4.7... and draws 2.7amps from the battery... On the other hand, when you set your voltage down to 3 volts on your same 2 ohm coil, it scales the voltage down, now only drawing 1.5 amps... You just went from vaping at 11+ watts to about 4+ watts...
On the other hand, when you set the wattage you're doing the exact opposite... When you say you want to vape at 4.5 watts it checks the coil and sees that it's 2ohms and outputs 3 volts.... When you crank it up to 11 watts it cranks up the voltage to 4.7 volts...
If on the other hand you leave it set for 11 watts and instead install a new 1.5ohm coil, it's going to drop down to around 4 volts to give you the same 11 watt output...
Hope all that makes sense... I know I tend to ramble a bit but I try to be as clear as possible without going completely overboard!