The Idea:
Like many others I have been fiddling with ideas as to how my New Protege will perform. One of the performance questions that crossed my mind was: How long will the battery last? After some farting around on the inter-web for a bit research, I think I may have come up with an idea as to how to approximate how long the Protege battery will last.
Variables:
1. Battery: 14500 3.7v 900mAh Li ion Battery
2. Average Draw Length: 5 sec (adjust to you habits)
3. Average Analog Cigarette's Number of Draws: 15 Draws (on the high end)
4. Number of Analog Cigarettes Per Pack: 20 Cigarettes
5. Number of Packs YOU Smoke/ Smoked A Day: 1 Pack (for me)
Battery Charge Basics:
Information Gleaned From Wikipedia:
An ampere-hour or amp-hour (symbol Ah , A·h, A h) is a unit of electric charge, with sub-units milliampere-hour (mAh) and milliampere second (mAs). One ampere-hour is equal to 3,600 coulombs (ampere-seconds), the electric charge transferred by a steady current of one ampere for one hour.[1]
The ampere-hour is frequently used in measurements of electrochemical systems such as electroplating and electrical batteries.
The commonly seen milliampere-hour (mAh or mA·h) is one-thousandth of an ampere-hour (i.e., 3.6 coulombs), and is a technical term for how much electrical charge a particular battery will hold. Small batteries, such as those in laptops and digital cameras, are often rated in milliampere-hours. As an example, digital camera batteries with higher mAh values theoretically last longer without requiring a recharge, allowing one to take more photographs before having to replace the batteries.
Calculation:
1. Protege Battery = 900mAh or 900 thousandths of an ampere-hour.
2. 1000mAh = 1 hr of steady current
3. 900 ÷ 1000 = 0.9%
4. 1hr = 60 min
5. 0.9 x 60 min = 54 min
6. So, 900mAh = 54 min of steady current
7. Average Draw (assuming) = 5 sec
8. 1 min = 60 sec
9. 54 min x 60 = 3240 sec
10. 3240 sec ÷ 5 = 648 Draws
11. Average Analog Cigarette's Number of Draws = 15 Draws (on the high
end)
12. 648 Draws ÷ 15 = 43.2 Analog Cigarettes
13. Number of Analog Cigarettes Per Pack = 20 Cigarettes
14. 43.2 Analog Cigarettes ÷ 20 = 2.16 Packs of Analog Cigarettes
15. Number of Packs YOU Smoke/ Smoked a Day = 1 (for me)
16. 2.16 Packs of Analog Cigarettes ÷ 1 = 2.16 Days of Regular Smoking
Conclusion:
If we lived in a perfect world, with no other variables present, 1 x Protege battery should last a 1 x Pack per day smoker 2.16 days. More realistically, with many variables tossed in (including hardware & operator issues), 1 x Protege battery should have no problem lasting whole day of vaping.
I would like to hear everyone's thoughts on this idea of mine, especially Steve & Casey's (as they have tested the Protege). Thanks for reading and I look forward to any thoughts / comments / replies.
Like many others I have been fiddling with ideas as to how my New Protege will perform. One of the performance questions that crossed my mind was: How long will the battery last? After some farting around on the inter-web for a bit research, I think I may have come up with an idea as to how to approximate how long the Protege battery will last.
Variables:
1. Battery: 14500 3.7v 900mAh Li ion Battery
2. Average Draw Length: 5 sec (adjust to you habits)
3. Average Analog Cigarette's Number of Draws: 15 Draws (on the high end)
4. Number of Analog Cigarettes Per Pack: 20 Cigarettes
5. Number of Packs YOU Smoke/ Smoked A Day: 1 Pack (for me)
Battery Charge Basics:
Information Gleaned From Wikipedia:
An ampere-hour or amp-hour (symbol Ah , A·h, A h) is a unit of electric charge, with sub-units milliampere-hour (mAh) and milliampere second (mAs). One ampere-hour is equal to 3,600 coulombs (ampere-seconds), the electric charge transferred by a steady current of one ampere for one hour.[1]
The ampere-hour is frequently used in measurements of electrochemical systems such as electroplating and electrical batteries.
The commonly seen milliampere-hour (mAh or mA·h) is one-thousandth of an ampere-hour (i.e., 3.6 coulombs), and is a technical term for how much electrical charge a particular battery will hold. Small batteries, such as those in laptops and digital cameras, are often rated in milliampere-hours. As an example, digital camera batteries with higher mAh values theoretically last longer without requiring a recharge, allowing one to take more photographs before having to replace the batteries.
Calculation:
1. Protege Battery = 900mAh or 900 thousandths of an ampere-hour.
2. 1000mAh = 1 hr of steady current
3. 900 ÷ 1000 = 0.9%
4. 1hr = 60 min
5. 0.9 x 60 min = 54 min
6. So, 900mAh = 54 min of steady current
7. Average Draw (assuming) = 5 sec
8. 1 min = 60 sec
9. 54 min x 60 = 3240 sec
10. 3240 sec ÷ 5 = 648 Draws
11. Average Analog Cigarette's Number of Draws = 15 Draws (on the high
end)
12. 648 Draws ÷ 15 = 43.2 Analog Cigarettes
13. Number of Analog Cigarettes Per Pack = 20 Cigarettes
14. 43.2 Analog Cigarettes ÷ 20 = 2.16 Packs of Analog Cigarettes
15. Number of Packs YOU Smoke/ Smoked a Day = 1 (for me)
16. 2.16 Packs of Analog Cigarettes ÷ 1 = 2.16 Days of Regular Smoking
Conclusion:
If we lived in a perfect world, with no other variables present, 1 x Protege battery should last a 1 x Pack per day smoker 2.16 days. More realistically, with many variables tossed in (including hardware & operator issues), 1 x Protege battery should have no problem lasting whole day of vaping.
I would like to hear everyone's thoughts on this idea of mine, especially Steve & Casey's (as they have tested the Protege). Thanks for reading and I look forward to any thoughts / comments / replies.
It's a lot simpler than doing that math! Hehe
hey cash will pure smoker be stocking vg juice in the near future thanks lots
