????'s for Shawn, Doc etc. on VX2 batts

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The Doc

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Jul 14, 2009
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Torrington, CT 06790
First off, the charger LED changes color when the charger switches to the lower current (trickle charging rate). The charger LED changing color does not mean the battery is fully charged. You should always break them in with the longer 8HR charge time. Regular charge time is unknown to me as of yet...but I'll bet it's in the range of 2-4 hours. Judging from battery size, I would say these VX2 Batts are rated for 180-300mA.....so 4 hrs should be MORE than enough charge time. AS far as the LED on your batts....they always act funny when they were recently charged. I let them sit awhile and they don't act so funny. You will also notice that IF you use the batts fresh off the charger...they will actually work BETTER after drawing current from them a few times then waiting a short while before puffing on them again. The chemical composition of these batteries have a tendency to get locked into one mode or the other...charge or discharge. They work better when they have a BREAK in between the two opposite current flow activities...which is exactly why I have several batts + USB passthrough for my VX2 units. I plan to save my VX2 batts ONLY for when I'm out & about. I have the USB passthrough PLUS a DSE601 epipe for when I'm home. The VX2 passthrough supplies me with very good vapor + rich flavor. The DSE601 epipe satisfies me when I need a HEAVY DUTY NICOTENE FIX (like after meals or various other extra-curricular activities).
 
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nephillim

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Jun 30, 2009
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I personally did not do the "8 hour" charge time. They stayed on the charger the first time for no more than 5 hours and so far my batteries are going strong as the day I got them. Typical charge time has always been less then 3 hours, I'm pretty sure I get the "blinks" at 2 hours, just usually not paying that much attention. The batteries are 0.81Wh and IF i converted that over correctly its 0.218Ah? I'm not sure if I did that right or not, maybe someone on here can correct me if I'm wrong. I'm pretty sure the equation is Ah*V=Wh (Amp-hours times volts = Watt-hours) so Ah*3.7=0.81 which means Ah=0.81/3.7 so Ah = 0.218Ah or 218 mAh.... If i didn't do that backwards, its been a few years since I've done much math. lol
 
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