Hey everyone. I jotted down some rough numbers to determine the correct juice density to replace my analogs and here is what I have so far.
My regular analog is a Marlboro Menthol Light, Hard Pack. According to the Erowid site under Plants,Tobacco (can't post links yet)
the nicotine per cigarette is approximately 0.7 mg for my particular brand.
So from here I took some basic information I found on the web to approximate the juice to the analog, where the density of the juice is mg/ml, so a 36 mg juice would contain 36 mg/ml.
Now from what I've read, a cigarette will last approximately 12 - 15 puffs which is roughly equivalent to 0.1 ml of juice, or 2 drops (0.05 ml/drop).
From this we can determine the ml/puff. There's no way to know how many ml/puff you're actually using when vaping because of variances in the atomizer, battery power, etc., so I'm just going to assume the lower amount is closer to the actual value as a rough estimate.
12 puffs: 0.1 ml / 12 puffs = .00833 ml/puff
Now since my particular brand has 0.7 mg / cigarette, we can determine the mg/puff.
12 puffs: 0.7 mg / 12 puffs = 0.0583 mg/puff
Multiplying the (ml/puff)* (puff/ml) yields the density:
(0.0583 mg / 1 puff) * (1 puff / 0.00833 ml) = 6.9987 mg/ml or 7 mg/ml.
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Now what I'm not understanding is why the juice comes in such high densities? According to that site, the highest nicotine amount is approximately 2mg / cigarette (English Ovals).
at 12 puffs: (2.0 mg / 12 puffs) * (1 puff / 0.00833 ml)= 20 mg/ml.
From this it would appear 36 mg density juice is roughly equivalent to 3.6 mg/cigarette which is the equivalent of 5.14 cigarettes of my current brand. Smoking 5 cigarettes at once doesn't exactly seem prudent.
However, I'm not sure as to the absorption efficiencies of analogs vs vapor though so my rough estimates may be off quite a bit.
Thoughts/Comments?
My regular analog is a Marlboro Menthol Light, Hard Pack. According to the Erowid site under Plants,Tobacco (can't post links yet)
the nicotine per cigarette is approximately 0.7 mg for my particular brand.
So from here I took some basic information I found on the web to approximate the juice to the analog, where the density of the juice is mg/ml, so a 36 mg juice would contain 36 mg/ml.
Now from what I've read, a cigarette will last approximately 12 - 15 puffs which is roughly equivalent to 0.1 ml of juice, or 2 drops (0.05 ml/drop).
From this we can determine the ml/puff. There's no way to know how many ml/puff you're actually using when vaping because of variances in the atomizer, battery power, etc., so I'm just going to assume the lower amount is closer to the actual value as a rough estimate.
12 puffs: 0.1 ml / 12 puffs = .00833 ml/puff
Now since my particular brand has 0.7 mg / cigarette, we can determine the mg/puff.
12 puffs: 0.7 mg / 12 puffs = 0.0583 mg/puff
Multiplying the (ml/puff)* (puff/ml) yields the density:
(0.0583 mg / 1 puff) * (1 puff / 0.00833 ml) = 6.9987 mg/ml or 7 mg/ml.
------------------------------------------------------
Now what I'm not understanding is why the juice comes in such high densities? According to that site, the highest nicotine amount is approximately 2mg / cigarette (English Ovals).
at 12 puffs: (2.0 mg / 12 puffs) * (1 puff / 0.00833 ml)= 20 mg/ml.
From this it would appear 36 mg density juice is roughly equivalent to 3.6 mg/cigarette which is the equivalent of 5.14 cigarettes of my current brand. Smoking 5 cigarettes at once doesn't exactly seem prudent.
However, I'm not sure as to the absorption efficiencies of analogs vs vapor though so my rough estimates may be off quite a bit.
Thoughts/Comments?