I am currently using a .25 ohm dual coil. Running my mod between 65 and 75 watts. I am not sure what battery I need as far as amps and MaH. I have seen some 18650's on ebay for a very cheap price but I am not sure if they are safe. Naturally I would like to get some batteries with the maximum MaH possible.
What battery do I need?
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Get Samsung 30Q's or LG HG2's.
Forget ebay or Amazon unless you know who actually ships authentic batteries and not counterfeits. I recommend one of these vendors...
www.liionwholesale.com
www.imrbatteries.com
www.illumn.com
www.rtdvapor.com
www.batterybro.com
www.orbtronic.com
www.nkon.nl
www.akkuteile.de
Welcome to Ecolux. The UK's Battery and accessory specialists. Wide range of authentic leading brands in stock ready for immediate dispatch.
Forget ebay or Amazon unless you know who actually ships authentic batteries and not counterfeits. I recommend one of these vendors...
www.liionwholesale.com
www.imrbatteries.com
www.illumn.com
www.rtdvapor.com
www.batterybro.com
www.orbtronic.com
www.nkon.nl
www.akkuteile.de
Welcome to Ecolux. The UK's Battery and accessory specialists. Wide range of authentic leading brands in stock ready for immediate dispatch.
With a regulated mod the resistance of the coil is essentially irrelevant.
Regulated mods separate the input and output voltage, in other words they separate the battery from the atomizer. The only relevant value is the wattage, and the remaining voltage in the battery. As the voltage falls, the mod will increase the amp draw to maintain the selected wattage. You need to know the amp draw at full charge, and when the battery is discharged as this value will be the highest. Most regulated mods are about 90% efficient, so you will also need to factor this loss into your calculations as it will marginally increase the amount of amperage pulled from the battery.
To find the amp draw use I=P/V (-10%)
Eg.
75w divided by 4.2v equals 17.8 divided by 0.9 = 19.8 amps
75w divided by 3.2v equals 23.4 divided by 0.9 = 26 amps
With multi battery devices, simply calculate the amp draw then divide by the number of batteries.
If you are using a single battery mod and you go with either of the batteries Mooch suggested, I would stay under 60 watts to be on the safe side.
Regulated mods separate the input and output voltage, in other words they separate the battery from the atomizer. The only relevant value is the wattage, and the remaining voltage in the battery. As the voltage falls, the mod will increase the amp draw to maintain the selected wattage. You need to know the amp draw at full charge, and when the battery is discharged as this value will be the highest. Most regulated mods are about 90% efficient, so you will also need to factor this loss into your calculations as it will marginally increase the amount of amperage pulled from the battery.
To find the amp draw use I=P/V (-10%)
Eg.
75w divided by 4.2v equals 17.8 divided by 0.9 = 19.8 amps
75w divided by 3.2v equals 23.4 divided by 0.9 = 26 amps
With multi battery devices, simply calculate the amp draw then divide by the number of batteries.
If you are using a single battery mod and you go with either of the batteries Mooch suggested, I would stay under 60 watts to be on the safe side.
Choose from the batteries and vendors Mooch listed. The prices will be surprisingly fair and you will get a REAL, authentic battery, not one that's been relabeled to be something it's not.
With the coil you are vaping, amperage rating is more important than MAH. The two Mooch recommended will give you a balance of both safe current ratings and vape time for your low resistance coil and wattage levels.
With the coil you are vaping, amperage rating is more important than MAH. The two Mooch recommended will give you a balance of both safe current ratings and vape time for your low resistance coil and wattage levels.
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