I thought the lower the ohms are the more liquid will be used up, but then at higher ohms you use more wattage. I think I'm draining more juice at 60w on my 0.4ohm coil than I was at 45w on a 0.25. Thoughts?
Less 0hms = more juice consumption
wattage is determined by the 0hms your coils use
anything above 1 0hm will most likely use less than 30 watts, ofc it varies by manufacturer,coils material,wicking etc
Overall less 0hms = more watts which = more juice vaporised.
I thought the lower the ohms are the more liquid will be used up, but then at higher ohms you use more wattage. I think I'm draining more juice at 60w on my 0.4ohm coil than I was at 45w on a 0.25. Thoughts?
0.25ohm Smok coils recommend 25-45w, but 55-65w on tha 0.4ohm..
Fixed it ... but why you're using more wattage on a higher ohm coil, if everything else is equal, I can't answer. There are many online calculators for ohm's law, but none factor in juice usage. That would be apples to oranges like. But yeah, you will likely use more juice subohming @ high wattage than I will on a Nautilus 1.8ohm coil @ 8.4W ... unless you don't take a pullI thought the lower the ohms are the more liquid will be used up, but then at higher ohms you usemoreLESS wattage (generally). I think I'm draining more juice at 60w on my 0.4ohm coil than I was at 45w on a 0.25. Thoughts?
Goes back to what VictorViper said about surface areaTo me, the type of coil is the biggest factor. I am using the "exotic" or fancy coils now and I see that they go through more juice than my older typical single wire builds.
I am using a fused clapton coil that ohms out at .35 and I have another tank that is using a regular clapton ohming out at .20. The juice consumption on the fused clapton is much higher than the clapton coil. Now, this is not an exact science and I am not going to do any tests to prove it one way or the other. This is just my observation.
Watts expresses the amount of energyproducedconsumed. The greater the amount of energyproducedconsumed, [the more heat produced and] the greater the volume of liquid vaporized in the chamber. [As heat is dissipated over a coil mass/area and the resulting heat causes the liquid to vaporize before cooling again and forming condensation.]
The greater the mass in a coil, the more surface area is available for energyproductionconsumption. [The additional energy required to heat the greater surface area to a temperature sufficient to vaporize liquid depletes a battery faster as well as the greater coil mass provides more area for the liquid to absorb coil heat and a greater amount of liquid to vaporize.]
That's why at any given resistance, a Smok Baby coil willsupport greater vaporizationrequire more wattage than a Nautilus coil to produce heat sufficient to vaporize liquid. [and provide a larger area for heat transfer in order for liquid to vaporize.]
With regulated mods [in VW mode],resistance is almost meaninglessas heat changes the coil resistance, wattage remains the same but voltage increases. It's the wattagedemanded by the userconsumed by the coil and the size of the coil [and the temperature and amount of heated area] that determines liquid consumption.
Put 80 Watts on a Smok BB and the cloud, bro. Put 80 Watts on a higher resistance [smaller wire] CE4 and the CE4 goes zzzzt! POP! [because the higher resistance (to current flow), smaller coil wire diameter can't handle the Amps/current flow demands of using higher watts.]
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~ Maybe you said it right, but that is how my mind wrapped around it LOL ... the only thing coils produce is heat, which in turn produces vapor ... or turns the liquid to a "gas" state as the liquid absorbs and dissipates the heat. ... and we haven't even talked about how airflow affects vapor production LOL. ... that's why a Billet Box, for example, using a 1.8ohm Nautilus coil and bridge will produce more vapor quicker at the same wattage than a 1.8ohm Nautilus coil in an Aspire Nautilus tank (original or mini). It's like a a dang Bermuda fire triangle ... Oxygen, Heat, Fuel (liquid) ... shoot
I still love that movie.On a regulated mod in a theoretical example, two coils of the same mass and surface area but differing resistances would produce the same amount of vapor at a given wattage, and therefore consume the same amount of juice.
In the real world a lower resistance coil would probably have greater mass and less surface area being that it would probably be built using a thicker wire. This coil would require more power to produce the same amount of vapor and consume the same amount of juice.
The reason that lower resistance coils are associated with higher power levels (and greater juice consumption) is that they are intrinsically better suited to higher power levels.
Understanding the relationship between power and coil resistance | E-Cigarette Forum
Watts expresses the amount of energy produced. The greater the amount of energy produced, the greater the volume of liquid vaporized in the chamber.
The greater the mass in a coil, the more surface area is available for energy production.
That's why at any given resistance, a Smok Baby coil will support greater vaporization than a Nautilus coil.
With regulated mods, resistance is almost meaningless. It's the wattage demanded by the user and the size of the coil that determines liquid consumption.
Put 80 Watts on a Smok BB and the cloud, bro. Put 80 Watts on a higher resistance CE4 and the CE4 goes zzzzt! POP!