Voltage drop explained?
- Thread starter JoshuaxHD
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Battery Voltage = Voltage accross coil + Voltage used by the mod itself.
The mod and battery have their own resistance.
If the total resistance of mod is 0.1 ohm, and your coil is 0.1 ohm, then your voltage drop is half.
Good info here
From the thread;
"A little more information.
Another major factor in assessing Voltage Drop is the internal resistance of the battery
I have just tested two batteries, the Panasonic NCR18650B 3400mah battery(green) and the Panasonic NCR18650 2900mah (grey)
The no load voltage of the 3400mah battery is 4.15V. The voltage with a .8 ohm coil firing is 3.6V. It has an internal resistance of <100 milliohms which is .1 ohms
The no load voltage of the 2900mah battery is 4.12V. The voltage with a .8 ohm coil firing is 3.8V. It has an internal resistance of <60 milliohms which is .06 ohms
So in all the drawings above there is another factor. All batteries have a resistance value. It is tiny but significant when sub ohming because of the increased current draw (more amps) when sub ohming.
So with the two batteries above it means that you will not have 4.15V and 4.12V volts with a coil firing, you will only have 3.6V and 3.8V available for the coil. So internal resistance of a lion battery is a very important factor often ignored. The lower it is the better. Lower quality batteries than the batteries I have used will give you a lower voltage available to your coil even though they may read 4.2V with no load. This has been my take on this, please correct me if I have made an error
So, you can have two different batteries reading 4.2V off load which give you a different vape experience."
Have fun
I
From the thread;
"A little more information.
Another major factor in assessing Voltage Drop is the internal resistance of the battery
I have just tested two batteries, the Panasonic NCR18650B 3400mah battery(green) and the Panasonic NCR18650 2900mah (grey)
The no load voltage of the 3400mah battery is 4.15V. The voltage with a .8 ohm coil firing is 3.6V. It has an internal resistance of <100 milliohms which is .1 ohms
The no load voltage of the 2900mah battery is 4.12V. The voltage with a .8 ohm coil firing is 3.8V. It has an internal resistance of <60 milliohms which is .06 ohms
So in all the drawings above there is another factor. All batteries have a resistance value. It is tiny but significant when sub ohming because of the increased current draw (more amps) when sub ohming.
So with the two batteries above it means that you will not have 4.15V and 4.12V volts with a coil firing, you will only have 3.6V and 3.8V available for the coil. So internal resistance of a lion battery is a very important factor often ignored. The lower it is the better. Lower quality batteries than the batteries I have used will give you a lower voltage available to your coil even though they may read 4.2V with no load. This has been my take on this, please correct me if I have made an error
So, you can have two different batteries reading 4.2V off load which give you a different vape experience."
Have fun
I
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