Is there a way to get a 5 volt mod to go down to 4.2 or 4.5? I like the consistency of the regulator but I like the fully charged 3.7 taste better. I would use a 2 amp half ohm resistor but I don't know where to get something like that.
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Just found .47ohm 2 & 3 amp resistors that I think would turn a 5 volt mod into a regulated 4.2(fully charged 3.7voltage) so it would be like a fresh battery the whole time your vaping. I am sure the shipping would be like 600 times the cost of these, anyone else interested in making a something like this? If enough people are interested maybe Madvapes could carry these so we could get them at there shipping rate when we order. You could also use these to make a mod switchable from 3.7 to five volts by using a toggle switch.
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Use a diode. Get one of these from radio shack. 3A Barrel Diodes - RadioShack.comIt will drop .8 volts, putting you right at 4.2. Put it in series with the atty, striped end towards the negative side of the circuit. If you get it backwards nothing will happen, so just reverse it if that happens.
I've always used 3/4 V drop for diodes like that, or .75 which isn't too far from .8 V. But I'm curious, which is right?
wonder if we could put that diode in an adapter... stuff is microscopic! screw it in and drop the voltage. want a heavier hit than screw it out...
wish madvapes had it!
wish madvapes had it!
if they carried diodes you could make a 510 version of this. Buy connectors for a 510 and a 402 (i think this is the one that is also a atty end for 510, its in the MV site anyway) and a diode and link them all togather. If you are making a 5volt mod and want switchable voltage build it with the diode and run a switch around the diode to bypass to get 5v.
401s, 402s, & 403s are all the same, the difference is in the battery length. &, I've been told that the 401 battery connector is the same threads as a 510 atty connector & vice versa. I know they will screw together.
It actually depends on the chemistry of the diodes. The ones I mentioned above dropped .8. I think the smaller signal or logic level diodes are .6, but they would be of no use in this application as they cant take the amps.
FWIW this is Nuck's FistPack diode that he says drop's .6V. It's a 2A, but that should be sufficent.
Digi-Key - B280-FDICT-ND (Manufacturer - B280-13-F)
from here.
[FONT=Arial, Helvetica, sans-serif]"Normal" diodes: Have a voltage drop between 0.6V and 0.7V
Schottky diodes: They have a low voltage drop (about 0.1V to 0.2V)
Light emitting diodes (LED): These diodes will emit a light when passing current. Their voltage drop will depend on the colour of the LED, but is around 2V to 3V.
Zener diodes: They behave as a normal diode for current flowing from the left to right, but will allow current to flow from the right to left if the voltage is high enough. You get a lot of different Zener voltage diodes, e.g. 4.7V and 12V....[/FONT]
You must always place a resistor in series with a diode to limit the current flow, if you don't do that the diode will act as a short circuit and draw current until the supply or the diode breaks."
[FONT=Arial, Helvetica, sans-serif]
[/FONT]
[FONT=Arial, Helvetica, sans-serif]
[/FONT]
[FONT=Arial, Helvetica, sans-serif]"The diode above will pass current flowing from left to right, but block current trying to flow from the right to the left-hand side. The voltage drop over diodes will vary from diode to diode, the most common ones are:[/FONT]
[FONT=Arial, Helvetica, sans-serif]"Normal" diodes: Have a voltage drop between 0.6V and 0.7V
Schottky diodes: They have a low voltage drop (about 0.1V to 0.2V)
Light emitting diodes (LED): These diodes will emit a light when passing current. Their voltage drop will depend on the colour of the LED, but is around 2V to 3V.
Zener diodes: They behave as a normal diode for current flowing from the left to right, but will allow current to flow from the right to left if the voltage is high enough. You get a lot of different Zener voltage diodes, e.g. 4.7V and 12V....[/FONT]
You must always place a resistor in series with a diode to limit the current flow, if you don't do that the diode will act as a short circuit and draw current until the supply or the diode breaks."
[FONT=Arial, Helvetica, sans-serif]
[/FONT]
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