Amps(Current) and dual-coils question.

[Adavicro]

Ok so I've been reading Baditude's guide on batteries and Ohm's law, and I'm sure I understand more about it than I did a couple days ago. I've applied Ohm's law on single coil builds to see if a coil is safe to use with X battery, and was wondering with a dual coil build for example, a 1 ohm dual coil (two 2 Ohm coils) is used with a 4.2v fully charged AW IMR 18650 1600 mah (24A) battery does the current of 24 amps split between them or does the same amount of current run through each coil? My physics is a little rusty, and I think the current splits?

 

[Scarey]

Your current for a single 1Ω coil is the same as the current for 2 parallel 2Ω coils that read at 1Ω.

 

[Hoosier]

Current is equal to voltage divided by resistance. (I=V/R)

The current discharge capacity is not used in the calculation, it is your reference point.

At 4.2 volts with a 1 Ohm load your current is 4.2 Amps which is well within the battery's capacity.

 

[Thrasher]

a 1 ohm dual coil (two 2 Ohm coils) is used with a 4.2v fully charged AW IMR 18650 1600 mah (24A) battery does the current of 24 amps split between them or does the same amount of current run through each coil? My physics is a little rusty, and I think the current splits?

you are correct it will split but it wont be the full current from the battery
Ohm's Law Calculator

if you punch in 4.2 v and 1 ohm you will see it is 4.2 amps so each coil will get 2.1 amps

the resistance decides the amperage draw, and that needs to be less then the maximum of the battery

 

[Adavicro]

Thanks for the confirmation, and to be clear 24 amps for that AW IMR battery is the max capacity of that said battery?

 

[patrao_n]

Depends for the 18650 1600 mah by aw like you have yes. 24 is the limit. For the 2000 mah version its less. And although it is stated to have a 24 max amp discharge I dont bring them near that. I usually run a .6 rather than th .18 ohm its max is

Sent from my SPH-L900 using Tapatalk