Batteries

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stubear62

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Sep 27, 2009
2,712
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Myrtle Beach, SC
Hi,
The volts on the 510 run @ about 3.1 and slowly die the more you use it before having to recharge the battery
As for the eGo and the XL eGo they both run @ about 3.4 volts until about the last two puffs you take. You will notice a very large drop in the way the eGo gives off the 2nd to last drag, and then the last drag it will blink and has to be recharged. The 510 battery will run from .5 hrs to approx. 2 to 2.5 hrs. This is due to how much you use it and how long you hold the button (manual battery).
The eGo (650mah) will last from 4 to 6 hrs (some have been 6 to 8 and 8 to 10 with a few getting anywhere from 10 to 72 hrs) Thats a big diff at the end there but those that do get that much time prob. take 1 to 2 puffs evey .5 to 1 hr. the norm is 4 to 8 hrs and again its how you use them and how long you hold the button down.
The XL eGo (900mah) can give you approx. 6 to 10 hrs and just add 2 to 3 to the other stes of time, again how you use it and hold down the manual button per puff.

The biggest thing with eGo's are they work very good using a LR atty, be it a 510 or 901 with the cone on. You wll need an adaptor for the 901. You can use an 801 LR atty but not with the cone. You will need to modify the cone (cut it down) to fit over the 801 atty due to its size. I have experianced only 1.2 hr diff using a 510 LR atty with my eGo compared to a reg 510 atty. (thats less time with the LR)

Hope this helpped..
 

zoltan

Full Member
Mar 30, 2009
7
0
What are the different Volts? (not mAh)

Joye 510
Ego
and the ego mega(900mAh)

I'm not sure about Joye, but my 510 (standard) puts out 4V unloaded (most probably LiPo cell 4.2V)
Janty Ego 650 mAh gives 3.5V
m402 - 2.8V

But it is not just the voltage - there is much in the power delivered trough the atty

Power is equal to:

P = U * I

where
P = power (in watts - W)
U = voltage (volts - V)
I = current (amperes - A)

Current is calculated from voltage and resistance:

I = U / R

where
U = voltage (volts - V)
I = current (amperes - A)
R = resistance (ohm)

for example eGo batt. with Janty Tawa atty

I = 3.5 V / 2.5 ohm = 1.4 A
P = 3.5 V * 1.4 A = 4.8W it is 4.9 watts of heat delivered trough the atty.

The bigest problem is that not all batteries are equal, and not all batteries can deliver the needed current. It depends of internal resistance of the battery. Lower is better, but we don't know what kind of cells are inside.
For example, you can look at batteries for electric vehicles. Many of them can deliver impressive amounts of current. This is rated at C rate.
C rate is the rate between battery capacity (for example 650 mAh) and the amount of current they can deliver. Higher C rating means more current. There are battery cells that can deliver as high as 175C safely (Saft VL 10V Fe Super-Phosphate can deliver 1750A) - but they are hell expensive. Our batteries are cheap (for manufacturer only, 'cause you can buy battery cell of 10Ah capacity witch can safely deliver 100A at 3.3V = 330W for less than 15USD and last for 2000 cycles instead of 300 like ours do).

I hope its not to technical, I tried to explain it simple (it's way more "behind the scenes")
 

MissEdie

Senior Member
ECF Veteran
Verified Member
Aug 9, 2010
100
7
Toledo,Ohio
therewardmouse.com
I was just asking,because I am not haveing much luck with a 5volt passthough.
Burns my throat and my lips.(yes the atty is wet):(
I use a cartomizer,but I am gonna be changing to the other ones.
I am not giving up yet
I'm not sure about Joye, but my 510 (standard) puts out 4V unloaded (most probably LiPo cell 4.2V)
Janty Ego 650 mAh gives 3.5V
m402 - 2.8V

But it is not just the voltage - there is much in the power delivered trough the atty

Power is equal to:

P = U * I

where
P = power (in watts - W)
U = voltage (volts - V)
I = current (amperes - A)

Current is calculated from voltage and resistance:

I = U / R

where
U = voltage (volts - V)
I = current (amperes - A)
R = resistance (ohm)

for example eGo batt. with Janty Tawa atty

I = 3.5 V / 2.5 ohm = 1.4 A
P = 3.5 V * 1.4 A = 4.8W it is 4.9 watts of heat delivered trough the atty.

The bigest problem is that not all batteries are equal, and not all batteries can deliver the needed current. It depends of internal resistance of the battery. Lower is better, but we don't know what kind of cells are inside.
For example, you can look at batteries for electric vehicles. Many of them can deliver impressive amounts of current. This is rated at C rate.
C rate is the rate between battery capacity (for example 650 mAh) and the amount of current they can deliver. Higher C rating means more current. There are battery cells that can deliver as high as 175C safely (Saft VL 10V Fe Super-Phosphate can deliver 1750A) - but they are hell expensive. Our batteries are cheap (for manufacturer only, 'cause you can buy battery cell of 10Ah capacity witch can safely deliver 100A at 3.3V = 330W for less than 15USD and last for 2000 cycles instead of 300 like ours do).

I hope its not to technical, I tried to explain it simple (it's way more "behind the scenes")
 

zoltan

Full Member
Mar 30, 2009
7
0
I was just asking,because I am not haveing much luck with a 5volt passthough.
Burns my throat and my lips.(yes the atty is wet):(
I use a cartomizer,but I am gonna be changing to the other ones.
I am not giving up yet

Don't give up! Clean the atomizer well and try after that. PT should be OK for most vapers. Maybe your juice is bad, what juice do you use?

Yesterday I was 18 months vaping and most problems came from bad juice.
 

zoltan

Full Member
Mar 30, 2009
7
0
Here is what Scottbee found when he did some test.

I read that. Data posted above is measured while I write that post and as I mentioned with no load connected.
For extended battery info best is to go and read on electric vehicle forums. They have huge sections dedicated only for battery technology. Try endless-sphere for start, they are maybe the biggest one.
 

petem

Super Member
ECF Veteran
Jul 24, 2010
345
0
va
Zoltan thanks for the info. You are way more into electronics than I am. I have to see if I can find it but seems to me somewhere on here there is mention of a circuit in the ego that regulates the voltage so that the ouput of power is more constant over the cycle of the battery if that makes any sense. This enables the atty to be more constant. Seems like there is not much drop off in vapor untill one or two hits before the battery flashes that it wants to be recharged. Have never found a tech reference for it so can not be sure.


edit: After reviewing the link further into the thread there is discussion of the board in the ego. These guys are deep into the equipment. Further than I want to go but I thank them for the info.
 
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