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Battery Confusion...

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Concat

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So if you stack two 880 mah batteries in a mod, do you effectively get 1760 mah? Or is it still 880 mah, just with double the voltage?

Also, a potentiometer adjusts the voltage, so with a simple unregulated VV mod, will the batteries drain quicker on a higher setting? Or is the voltage unrelated to battery life?

Ohm’s law states I = V/R. Since the resistance is static, I would think that a reduction in voltage would also reduce the amps and increase battery life.

Just trying to wrap my head around how stacked batteries + potentiometer affects battery life.
 

lickwid

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Two stacked 880mah batteries is still just 880mah with twice the voltage.

The battery usage is based on the Volts and the Resistance of the atty, something like if you using 3v on a 1.2ohm atty it'll use the same as 4v at 2ohm. These are just examples, I forget the actual formula.

Edit: I asked something similar awhile ago, link: http://www.e-cigarette-forum.com/forum/provape/158128-battery-question.html
 

Concat

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Hmmm… see I’m still confused.

Consider this scenario.

I have one 3.7 V 880 mah battery running on a 3.7 volt mod. Using Ohm’s law, and knowing the resistance of the atomizer, you can calculate the running amps, and thus the battery life.

I also two stacked 3.7 volt 880 mah batteries running on a VV mod. The voltage is adjusted to 3.7 volts. Again using Ohm’s law you would calculate the exact same battery life as the previous example (if we assuming two stacked batteries is still 880 mah).

How does that make sense? Two batteries stacked, with the voltage adjusted last just as long as one battery without any voltage adjustment?

And thanks for the link Switched. Informative, for sure, but doesn’t discuss VV or potentiometers. :(
 
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NoizMaker

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I'm fairly certain that most mods are connected in series, so your math does make sense.

When you stack batteries you are seeking to change the voltage and not the mAh, however if you connect the same batteries in parallel then you keep the voltage and boost the mAh (but I can't think of many mods that do this, anyone know of any?). Essentially it is in the way the circuit is built to handle the power source.
 

Chime

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Which generates more watts we can get really esoteric here if you want ;)

Simple way of under standing it tho series circuits (aka stacked batteries) combine voltages, parralel circuits (your boombox(lol I'm old)) combine current (amperage).

mAh is really a property of battery chemistry/construction and has little to do with resulting amps, it's just an arbitrary measurement of how much water is in the bucket, it has little to do with how big a hole you drill in the side.
 

Can_supplier

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however if you connect the same batteries in parallel then you keep the voltage and boost the mAh (but I can't think of many mods that do this, anyone know of any?).

A bigger battery is the same as 2 smaller batteries in parallel. So in essence it is what a 510 is to an eGO battery.
 

Switched

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I'm fairly certain that most mods are connected in series, so your math does make sense.

When you stack batteries you are seeking to change the voltage and not the mAh, however if you connect the same batteries in parallel then you keep the voltage and boost the mAh (but I can't think of many mods that do this, anyone know of any?). Essentially it is in the way the circuit is built to handle the power source.
My 14500 parallel box for efficiently vaping LR.
 

TallGrass

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A bigger battery is the same as 2 smaller batteries in parallel.

basically except that the two smaller batteries will better handle large current draw. Check the datasheet on your favourite battery and the max draw might be 1.2-1.5 amps (as an example)... you're blowing way past that with a LR atty @ 5V. Two high-drain batteries in parallel = unbreakable.
 
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