Battery output voltage

[SP3C1ALSAWC3]

I wanted to see if someone could point me in the right direction to learn more about battery outputs at certain wattages.
For instance, if my VTC 5 has a full charge @ 4.2 watts and I make a .5 ohm build on my ipv2, and crank it to 50 watts, it says it's putting out 5.3V.

how can this be? Any explanations are appreciated. Links for information also appreciated.
just trying to learn more about these batteries before I move on to a mech.

thanks again!

 

[Ryedan]

What is generally used is a buck/boost dc-dc converter. The link will get you started if you want to investigate these more.

The power (watts) pulled from the battery equals the power output from the device plus inefficiency loss from the converter.

Amps (battery) = watts (device output) / volts (battery)

Then adjust for inefficiency loss percentage.

Or you can use the Steam Engine calculators, Ohm's law or better yet battery drain.

 

[classwife]

Moved to Variable Voltage APV Discussion from APV Discussion

 

[Kumatesh]

Let me repost what a gentleman on reddit asked as this should answer all your questions and then some

Hello! I just got into modding and have a nemesis mod with a 10 amp battery. I just figured out how to maximize my power draw by building my coils to the lowest resistance possible without over drawing on the amps. I still don't know how to maximize my clouds with different gauges/wraps and dual or single coils but that's not the question.
I am thinking about getting the IPV2 50w box mod but cannot seem to wrap my head around a few things
1. How is that the regulated mod can push 6+ volts if the battery only charges to 4.2. Capacitors in the mod?
2. I saw that a higher resistance coil is better because the amp draw is lower and will prolong your battery life. and you can make up for the higher resistance by pushing more watts. but if you're pushing more volts/watts won't that drain the battery faster?
3. Should I still follow ohm's law in a regulated mod. If I have a 10 amp battery should I still only build above .5 ohms? Because 4.2/.5 = 8.4
4. Most importantly, can I use a 10 amp battery in this mod? I couldn't find anything online.

And here was my response:

1. It can do this by using what is known as a "boost circuit." The chip will pull in more amps from the battery to boost the voltage in order to provide your requested wattage
2. The atomizer resistance on a regulated mod is negligible at best. There may be -slight- differences due to inefficiencies in the chip. Your battery life will depend solely on your wattage. The formula for this is (P/Vi)+Inefficiency = I. P = watts, Vi = battery voltage, I = amps. Inefficiency will depend on the chip but most are 90-95% efficient so the factor would be 5%-10%.
3. Ohms law never goes away but refer to #2
4. Refer to #2. In short, no, a 10amp battery is insufficient. You would need a battery capable of around 20amp continuous to vape safely at 50w. Always use worst-case scenario when determining amps for batteries. We'll take the 50w for your mod, say that the battery is 3.2v (where your mod would cut off to protect the battery), and the inefficiency is a whopping 25%. (50w/3.2)+25% = 19.53a