Calculating advanced coil builds ohms?

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SLIPPY_EEL

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Oct 11, 2013
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you can make your wire first and then feed enough wire between your pos+ & neg- posts to match the desired ohms, you dont have to actually have a coil for to be able to test the wires ohms on a meter.
if you use the steam engine calc you can find out what twisted wires, parallel's or single core wire will work out to in ohm's + length and in most cases if i remember rightly the power only runs through the core wire anyway, the clapton gets heated from the core not from voltage so you should be pretty close.

and once you get a bit of experience you will know exactly what you can and cant use
 
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Mden89

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you can make your wire first and then feed enough wire between your pos+ & neg- posts to match the desired ohms, you dont have to actually have a coil for to be able to test the wires ohms on a meter.
if you use the steam engine calc you can find out what twisted wires, parallel's or single core wire will work out to in ohm's + length and in most cases if i remember rightly the power only runs through the core wire anyway, the clapton gets heated from the core not from voltage so you should be pretty close.

and once you get a bit of experience you will know exactly what you can and cant use

Im sorry can you dumb this down even further for me. I must be special because im not understanding what you are saying. I see the whole clapton coil being fed into the posts so wouldnt every piece of coil be getting power, not just the core?

Also, i dont get what you mean by "Making my wire first then feeding enough through the posts to match the ohms". How does this help me understand how to calculate the ohms for more advanced coils like the clapton coil
 

Braaapp

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Feb 25, 2012
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For a clapton the only resistance that matters is the core wire, since the outer wrap is a radiator and not affecting the resistance. You would build the coil in steam engine with just the core wire gauge to the resistance you wish. If your wrapping wire is, say 30ga (0.255), and you're wrapping on a 2mm diameter shank you would add 2x0.255 (0.51) to the inner diameter measurement (for a total of 2.51mm ID) because the wrap is adding that much inner diameter to the actual core wire inside of the coil.

For more advanced builds like multiple different gauges twisted together, about the only way to get an accurate idea of the resistance is to make a length of wire long enough to build your coils and measure the actual resistance per mm with a multimeter or ohm meter by doing what slippy_eel said. The longer the length, the more accurate it will be. So you would mount about 30cm of the wire in your rda/rba and measure the resistance, then divide resistance by mm of length. In steam engine you input this number into the advanced area to get the number of wraps, etc.
 
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SLIPPY_EEL

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the flow of electric will travel the path of least resistance which is your thicker gauge wire, but you can also have wires where the current travels through all the wires but the wires need to be very tight to one another.

sometimes when you make these clapton wires and other exotic wires there isnt a lot of info on what the ohms would be or say you just want to be a bit more precise on the ohms, so in this case you could have an atty sat on your ohm reader and you would thread your wire through the posts of your atty and by adjusting the length of wire and testing the ohms you could find out, obviously you would thread the wire and tighten the posts onto the wire test ohms and adjust from there, simple but im also terrible at explaining so its not all your fault.

or failing this you could get some info from someone on whats a good clapton to build for the ohms you vape at.
 

HiSpdLoDrg

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May 28, 2014
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I am no electrician, but this is the math behind "theoretically" calculating the resistance of multiple strands.
(source link: How to Calculate Series and Parallel Resistance (with Cheat Sheets)
  • The equation for combining n resistors in parallel is:
    Req = 1/{(1/R1)+(1/R2)+(1/R3)..+(1/Rn)}
  • Here is an example, given R1 = 20 Ω, R2 = 30 Ω, and R3 = 30 Ω.
  • The total equivalent resistance for all 3 resistors in parallel is:

    Req = 1/{(1/20)+(1/30)+(1/30)}

    = 1/{(3/60)+(2/60)+(2/60)}

    = 1/(7/60)=60/7 Ω = approximately 8.57 Ω
 
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