Calculating battery discharge time

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dnglos

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Jan 6, 2013
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According to my Ohm's Law calculator, running a 2.0 ohm coil at 4.0 volts produces 8 watts of power with a current of 2000 milliamps.

To calculate how long a fully charged battery would take to fully discharge I figured you'd use the formula mAh/mA, but for 900mAh that gives 900/2000 = 0.45 hours - which is clearly not right.

What am I doing wrong? Anyone?
 

Rader2146

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It means if you were to hold the button down without letting up, it would take .45 hours for your battery to be completely drained.

Since we only hold the button down a couple seconds at a time, it all depends on your vaping pace. A chain vaper might drain a battery in 3 hours where a light vaper might take 8 hours.

There are more variables too, like usable capacity vs rated capacity, but that is really getting down to the brass tacks.
 

WillyB

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Oct 21, 2009
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This may help put things into perspective.

14500ic_800mA_600mAh_2.jpg


Even at a rather paltry .8A drain we see that the 900mAh cell is only 592mAh and at a constant drain it lasted 44min.

All mAh ratings have to taken with a grain of salt, Panasonic with it's Li-Ions uses a 2.5V cut-off, not appropriate for our use. With their gray high drain they use a measly 430mA drain to establish the 2250mAh rating.
 

dnglos

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Thanks to everyone for taking the time to respond. I'm starting to think the '1 hour per 100 mAh' rule is a bit of a myth - unless you're a very light vaper. I don't consider myself a particularly heavy vaper (I get through about 30ml of juice per week), but for me a single 18350 battery lasts a couple of hours at best before it needs recharching.
 
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