Calculating Power?
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Voltage squared divided by ohms = watts. The number of coils is irrelevant as a standard dual coil is two 3.2ohm coils in series which is seen as 1.6ohms by the device.
Mindfield is correct. The device doesn't know how may coils there are... it's only 1.6 ohms to it.
However, as an added note, if you want watts-per-coil then you would divide by # of coils.
Now even 24 watts over 2 coils .... 12 watts per coil. Too hot. That would be 6.2 volts and 3.8 ish amps.
What #'s or device are you using for your calcs?
However, as an added note, if you want watts-per-coil then you would divide by # of coils.
Now even 24 watts over 2 coils .... 12 watts per coil. Too hot. That would be 6.2 volts and 3.8 ish amps.
What #'s or device are you using for your calcs?
Using two 3v RCR123s. I'm getting a median of 6.2v, 1.2amps and on my carto a solid 1.5ohms. Ohms law says I should have 4.1amps though.. This is frustrating me :/ I hope my multimeter isn't @#$%ed. It seems to get the correct voltage and resistance.. But it's probably just user error :/
The 1.2 amps, is that a measured amperage or just your calculation
Assuming you have a decent Multi-Meter and you know how to properly read it,
measure your atty/carto resistance, attach atty/carto and measure voltage and current draw.
DON'T rely on Ohm's Law. You're calculations will be way off compared to what you are actually getting.
Current and Wattage is subjected to your regulator and battery limitations.
I've made these comparisons with the 08100w w/ two batts in series and w/ different batt models and mah's.
Also w/ the 04050c w/ 1 batt and w/ two batts in parallel and w/ different batt models and mah's.
measure your atty/carto resistance, attach atty/carto and measure voltage and current draw.
DON'T rely on Ohm's Law. You're calculations will be way off compared to what you are actually getting.
Current and Wattage is subjected to your regulator and battery limitations.
I've made these comparisons with the 08100w w/ two batts in series and w/ different batt models and mah's.
Also w/ the 04050c w/ 1 batt and w/ two batts in parallel and w/ different batt models and mah's.
Using a Fluke 23 meter, and yes, 1.2 is my measured amperage. Calculated is 4.1 which seems waay off. It's drawing 4.5 volts. With the 1.5ohm dual coil cartomizer, do I put 1.5 ohms into the calculator? Or is it 3..? I know it has been said that my device can't tell the difference when it's in circuit but the solution makes more sense when I use 3 ohms versus 1.
4.5v, 1.5 amps, 3 ohms, 6.75 watts
4.5v, 1.5 amps, 3 ohms, 6.75 watts
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You can't be measuring amps without load across the meter. The meter has to take the load.
^ Jackpot... I need to hold on to a few cartos after they die, as they now have a date with the dremel coming soon.
For post #8 - read post #3 again. The way you did it with the 3 ohms... you'd need twice the amps from the battery since you have two 3 ohm coils (and actually they are about 3.2 ohms - could be real-world 3.0). Or just use the 1.6 ohms for the calc. Of course, if you're measuring actual values with the Fluke.... Actual volts X actual amps = actual watts.
LiIon batteries can only put out so many amps. IMR batteries do better. IDK if they have 3 volt IMRs, since I don't vape at 6v.
LiIon batteries can only put out so many amps. IMR batteries do better. IDK if they have 3 volt IMRs, since I don't vape at 6v.
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Your calculations on right, but the watts are spread across two coils.
It does matter the number of coils. You can slam a 1.5 ohm dual coil over 5 volts with no burning. Thats how they do it.
It does matter the number of coils. You can slam a 1.5 ohm dual coil over 5 volts with no burning. Thats how they do it.
The confusion seems to be that he juggling two different wattage issues in his head.
The 1st posts asked how many watts is my mod dealing with?
That's total wattage drawn from the battery and mindfield's answer is correct from that perspective. The device doesn't know nor care how many coils there are.
Later, the OP is calculating watts per coil on a Dual Carto. A different calculation, since you basically divide the total watts by two. Or you can calculate it using single coil ohms and single-coil amps and then multiply the watts and the amps by two since it is a DC.
So OP, for a 1.6 ohm DC at 6 volts you draw a total of 22.5 watts 3.75 amps THEORETICAL
That's 11.25 watts per coil (22.5 / 2). Too hot.
Your actual will vary under load and with different battery chems (like high-drain vs standard). They have to be measured directly with your mm, and then volts * amps = watts. watts/2 = watts per coil in a DC.
The 1st posts asked how many watts is my mod dealing with?
That's total wattage drawn from the battery and mindfield's answer is correct from that perspective. The device doesn't know nor care how many coils there are.
Later, the OP is calculating watts per coil on a Dual Carto. A different calculation, since you basically divide the total watts by two. Or you can calculate it using single coil ohms and single-coil amps and then multiply the watts and the amps by two since it is a DC.
So OP, for a 1.6 ohm DC at 6 volts you draw a total of 22.5 watts 3.75 amps THEORETICAL
That's 11.25 watts per coil (22.5 / 2). Too hot.
Your actual will vary under load and with different battery chems (like high-drain vs standard). They have to be measured directly with your mm, and then volts * amps = watts. watts/2 = watts per coil in a DC.
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AttyPops, I mentioned that I was using a dual coil carto in my original post. But I appreciate your POV. It seems to me that the dual coil element was throwing me off. Stownz, thanks for the clarification.
That's what I suspected. I'm now getting predictable results from my measurements.
Again, thank you everybody for your help.
That's what I suspected. I'm now getting predictable results from my measurements.
Again, thank you everybody for your help.
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