Dilution with 3 bottles

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zoiDman

My -0^10 = Nothing at All*
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Apr 16, 2010
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This may be simple math but i am stumped. I have two bottles of 6mg x 120 and one bottle of 0mg x 120ml. What % nic will I have mixing all three bottles?

thanks

Hi Sabraxx. Welcome to the ECF.

Nicotine Levels, in mg/ml, is Equal to Total Nicotine divided by Total Volume.

If you have Two 120ml Bottles of 6mg/ml e-Liquid, you have (120 x 6) + (120 x 6) = 1,440mg of Nicotine.

Since you have Three 120ml Bottles, your Total Volume would be 360ml.

So your Nicotine mg/ml if you Mixed all Three Bottles together would be 1,440mg / 360ml = 4mg/ml.
 
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