I'm not sure I understand your question, but I'll have a smack at it. The coil is a resistance. If two resistances are placed in series-- one after the other-- they will add and the resistance value is R1 + R2. If they are placed in parallel-- that is, side by side with the voltage free to enter either, and the return path joins together below them-- the issue is more complex. If the resistance is the same in both coils, half of the voltage will flow through each; if not, the amount going through either one is equal to the inverse of the percentage of the total each one represents. Example: in a parallel set up, with a 90 ohm resistor in parallel with a 10 ohm resistor, the 10 ohm will carry 90% of the voltage and the 90 ohm will carry 10%.
That, however, is probably not the question you wanted to ask. From your point of view--
vaping-- you don't have to think about it at all. From this perspective, "dual coil" means that there are two of them; and thus more coil wire surface to evaporate juice. As for resistances, if you're using the pre-made coils that screw into the bottom of the tank-- and you are on an iClear 30-- the total resistance is the value of the coil head as sold to you, 1.2 ohms or whatever it says on the box. (It will vary a tad due to manufacturing inaccuracies, but not enough for you to worry about.) If you are building a coil set on the deck of an RBA, RTA or RDA, what you need to know is a) build the coils so they are each the same ohms, by using the same wire and the same number of wraps around the same mandrel for both of them; strive for identical parts. And b), the total value of the resistance, used to figure the watts of your vape and the amps you're laying on the battery, is half the value of either of the coils; thus 2 x 4.4 ohm coils in parallel yield a total resistance in the atty of 2.2 ohms.
If that doesn't clear it up, ask another question and I'll try again
