Finding amperage.

[notawoman]

So, I'm kind of confused. I've seen examples go both ways and couldn't find a real answer in search. I'm trying to find the actual I'm at on my atomizers. Would I be dividing the current battery voltage by the resistance of the coil? Or do I have to account for the voltage drop of the mechanical divided by the ohms of the coil?

 

[E_DeCastro]

unless you can get a lead onto the positive post (like on a genesis style) it will be hard to get the actual voltage drop. voltage divided by the resistance will give you the current draw.

 

[CloudZ]

Yes and yes. The exact amperage will depend on internal mod/battery resistance (voltage drop), but it is actually safer to ignore the voltage drop and just use battery voltage and atomizer resistance. That way the real number will always be lower than what you think it is.

So yeah, if you can measure voltage drop or internal resistance, you use the "dropped" voltage divided by the atty ohms to get the real amps. Or, the battery voltage divided by the sum of the atty and internal ohms. The numbers here will be similar and close to exact, but the latter is less accurate due to under-load losses of the battery.

 

[JKuro]

Or you can build an ammeter. A voltmeter will be added to show voltage drop, and later models will also have an ohmmeter.

 

[notawoman]

Thanks everyone, I appreciate all the input. I just want to be as informed as possible since im working with sub ohm builds.