Help: Down to my last 5V regulator

Status
Not open for further replies.

TWalker

Senior Member
ECF Veteran
Dec 6, 2009
227
18
60
NM
I ordered some regulators with control pin months ago and just got around to building my 5V boxes with 2 14500 batteries.

They seem to work intermittently and then not at all so I'm going to throw in my last one tonight. I get the about 8V at input pin and about 5v at the output and I get good 5v vapes when it works but it is so sporadic, I can never tell if it is going to work.

I use a 12v 5amp horn style switch and no LED so I'm wiring no resistors to anything. Must I use resistors?

It seems as if I wire voltage in and out in the right pins and I get 5v out all should be good no?

Every diagram I look at has resistors and led's or microswitches so Its hard to tell.

Thanks


Edit: I read in another thread my switch must go before the regulator but since I didn't want to over tax the switch I wired it like this:

2 14500 in line> pin1 input on regulator>Pin 2 5v output to switch>switch to + on atty

both grounds (atty and master switch to pcb board ground pin number 3)

I'll diagram it if necessary, but it is 4 wires pretty straightforward.
 
Last edited:

TWalker

Senior Member
ECF Veteran
Dec 6, 2009
227
18
60
NM
Your switch belongs on the input to prevent power from going into the regulator, not the output. Your regulator is never shutting down the way you have it wired.


Odd it never was hot or anything until I hit the switch, but it did always have a consistent 7+ - 8 volts.

Can anyone tell me can I just the leave the (4th) control pin alone? (This is the Madvapes regulator)

I have resistors here but don't want to use them unless I need to.

Thanks
 

Connman

Super Member
ECF Veteran
Verified Member
Dec 6, 2009
903
52
62
North Florida, USA

CapeCAD

Senior Member
ECF Veteran
Verified Member
Jun 2, 2010
232
25
Massachusetts
Using the control pin takes all the current out of the switch, but you will need a resistor to ground for this work. Leaving it open like you did will leave the regulator on so you need to use the switch to cut the power (or ground) to the input of the chip.

I'm pretty sure the reason it did not get hot is you cut the load from the output with the switch, but the regulator stayed on.
 
Last edited:

TWalker

Senior Member
ECF Veteran
Dec 6, 2009
227
18
60
NM
Using the control pin takes all the current out of the switch, but you will need a resistor to ground for this work. Leaving it open like you did will leave the regulator on so you need to use the switch to cut the power (or ground) to the input of the chip.

I'm pretty sure the reason it did not get hot is you cut the load from the output with the switch, but the regulator stayed on.

I assume you used a normally closed switch if it was working when you pushed the switch. For this to work you should use a normally open switch on the input that will only work when pushed.

Ahh. I see, I think.

I'm not using the 4th pin but I do have the switch in front of the regulator.

While I was waiting I put it together with switch in front of regulator and it seems to work fine. I'm waiting for the liquid tape to dry for final enclosure. But it seems ok for now.
 
Status
Not open for further replies.

Users who are viewing this thread