Please let me see if I have understood correctly. With a regulated mod you can set the voltage and watts that you wish.
Almost. With a regulated mod, you set either wattage
or voltage; the other will adjust accordingly, based on the attached resistance (atomizer). You can't set them both, independently of one another.
Amps = Volts / Ohms
Watts = Volts^2 / Ohms
... = Volts * Volts / Ohms
... = Volts * (Volts / Ohms)
... = Volts * (Amps)
... = Volts * Amps
Watts = Volts * Amps
Volts = Watts / Amps
Amps = Watts / Volts
...these are all different ways of saying the same thing, and there is nothing you can do to make these equations untrue. So if you change anything on
one side of the equation, something
has to change on the other side as well, to maintain the equivalency.
With a mechanical or unregulated mod, the danger comes in working your battery past its limits by drawing too high of a current (amp draw.) So in order to remain safe, you must know the
maximum continuous discharge rate (CDR) of your battery (note:
continuous discharge rate,
not the "pulse" or "peak" discharge rate as that is a meaningless figure for our purposes) and select a resistance that will keep you well within that amp limit. Do all your calculations at 4.2v, as for a fully-charged battery.
In a regulated or variable mod, keep in mind that the amp draw is affected
only by the power setting (and the charge state of the battery), and
not by the attached resistance. This is because, no matter what the settings are, the battery itself is only ever outputting a single voltage (based on the charge state, 4.2v at full charge, and less as the battery begins to drain.) So if you're set for 50 watts, for example, and your battery is at 4v, then according to Amps = Watts/Volts, you are drawing 50/4 = 12.5 amps off the battery, regardless of whether you're pumping those 50 watts into a 2-ohm load or a 0.2. In this case, the device's internal circuitry
should keep you protected but, just to be on the safe side, note that the amp draw is higher when the battery is
depleted,
not when it's fully charged as would be the case with a mechanical device, and so your safety calculations should be done assuming a lower voltage of around 3.2v, or whatever the cutoff is for your particular device.