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woolfe99

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I just ordered 3x48mg bottles of AC, plus a doubler, for a total of 7 ounces of liquid. If my calculations are correct, that should make 7 ounces of 20.57 mg AC, assuming I just mix all of it together. Is that correct or are my maths off?

Not trying to hijack your thread Domino, just thought it was better to ask here rather than create a new thread.

- wolf
 

MastiffMike

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I just ordered 3x48mg bottles of AC, plus a doubler, for a total of 7 ounces of liquid. If my calculations are correct, that should make 7 ounces of 20.57 mg AC, assuming I just mix all of it together. Is that correct or are my maths off?

Not trying to hijack your thread Domino, just thought it was better to ask here rather than create a new thread.

- wolf


You are correct provided you're using the whole bottles.
 
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curiousJan

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Order 48 mg of AC and a bottle of doubler. Use half of each to cut your 48 to 24 mg. So in your empty bottle, half of the 48 mg and half of the doubler in other words.

Uhm ... that would be correct if the doublers came in 1 oz bottles. They are 4 oz bottles.


Ordering 4 48mg 1oz bottles and 1 0mg 4oz doubler would yield 8oz of 24mg/mL niquid.

Jan
 

Poeia

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I read all about doublers. I get that part. But, if I want to make a bottle of 24mg A.C. , what am I ordering and THEN what do I do with them? :confused: :oops:
Domino, as Rosesense said, mixing half 48mg and half doubler will give you 24mg AND one bottle of doubler will be enough to do that to 4 bottles of 48mg e-liquid. So the next 3 times you buy AC you'll only need to buy the e-liquid.
 

Whizdumb81

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I'm sorry, and I'm not a genius but everybodies math seems a bit off. Half a doubler would be 2oz.. if you mix 2 oz of 0mg and 1 oz of 48mg then you would be getting 1/3 of the 48mg resulting in 3 oz of 16mg AC. To cut the 48 in half you must do 1oz 48mg plus 1oz 0mg. Think about it logically, if you have equal parts of zero strength something and any strength something they will have to meet in the middle.

Long story short, for 24mg AC mix your 1oz 48mg bottle with 1/4 of your doubler bottle. Sorry if i'm wrong or stepped on anybodies toes but it just didn't seem right.
 

Poeia

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I'm sorry, and I'm not a genius but everybodies math seems a bit off. Half a doubler would be 2oz.. if you mix 2 oz of 0mg and 1 oz of 48mg then you would be getting 1/3 of the 48mg resulting in 3 oz of 16mg AC. To cut the 48 in half you must do 1oz 48mg plus 1oz 0mg. Think about it logically, if you have equal parts of zero strength something and any strength something they will have to meet in the middle.

Long story short, for 24mg AC mix your 1oz 48mg bottle with 1/4 of your doubler bottle. Sorry if i'm wrong or stepped on anybodies toes but it just didn't seem right.
Not half of each bottle, the mixture should be half and half.

One ounce of 48mg e-liquid plus one ounce of 0mg doubler = 2 ounces of 24mg e-liquid.
 

minxy_fox

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This one gets me every time I think on it. Why is it so confusing? I think because the nic bottle is one ounce, whereas the doubler is 4 ounces. So, in my way of thinking, you only use 1/8 bottle of the doubler to half a bottle of the nic liquid. this is assuming your nic is 48mg and you are wanting to make it 24mg. Therefore, with one 4 ounce doubler, you are able to make 8 one ounce bottles.
Argh .... my brain is all confused again. Please correct me if I'm wrong.
 

Gribeau

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Whiz, I think you might be misunderstanding a couple of previous posts. Jan and Poeia both made correct statements. Your math is also correct, it's just that all 3 of you are getting to the result a little differently.

Jan said 4X 1oz bottles of 48mg + 1 4oz bottle of doubler = 8oz of 24mg juice.
That is right.

Poeia said making a mixture where half of the mixture is 48mg and the other half is doubler yields a 24mg result.
That is right.

I'm not actually attempting to be an intarweb cop right now, nitpicking at minor stuff. I just don't want the less mathematically gifted amongst us to get even more confused upon seeing you say those two examples were wrong. :D
 

5cardstud

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This one gets me every time I think on it. Why is it so confusing? I think because the nic bottle is one ounce, whereas the doubler is 4 ounces. So, in my way of thinking, you only use 1/8 bottle of the doubler to half a bottle of the nic liquid. this is assuming your nic is 48mg and you are wanting to make it 24mg. Therefore, with one 4 ounce doubler, you are able to make 8 one ounce bottles.
Argh .... my brain is all confused again. Please correct me if I'm wrong.
The reason one is one ounce and the other is four is for the people that want to make 12 mg. juice or lower.
 
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Poeia

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minxy, I can't do it with fractions. I can, but it's not worth the effort. Think of it as "parts" and do an average. It doesn't matter whether a part is 10 drops, an ounce or a gallon. The math is the same. (ETA: Not "math," it's just arithmetic.)

If you have 48mg e-liquid and 0mg doubler and you combine 2 parts of e-liquid and 1 of the doubler:
48 + 48 + 0 = 96
96/3 = 32

If you combine 1 part of e-liquid and 1 part of doubler:
48 + 0 = 48
48/2 = 24

If you are combining the entire bottles a "part" is one ounce:
48 + 0 + 0 + 0 + 0 = 48
48/5 = 9.6

You add the milligrams in each of the parts including the 0s and divide by the number of parts.

I don't have a good eye for size so when I'm combining I'll think I have enough room in the little bottle for 60 drops and I'll put in 40 + 20 (if I'm doing a 2+1 mix.) Then I'll see the little bottle is well less than half full so I'll add another 60 + 30. Or, when I'm adding drops from one, I'll get carried away and put in 47 drops. If the mix is 2+1 that just means I have to add two times 47 (also known as 94) of the other one. As long as I get the ratio of how many parts of A to how many parts of B correct, it works.
 
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minxy_fox

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minxy, I can't do it with fractions. I can, but it's not worth the effort. Think of it as "parts" and do an average. It doesn't matter whether a part is 10 drops, an ounce or a gallon. The math is the same. (ETA: Not "math," it's just arithmetic.)

If you have 48mg e-liquid and 0mg doubler and you combine 2 parts of e-liquid and 1 of the doubler:
48 + 48 + 0 = 96
96/3 = 32

If you combine 1 part of e-liquid and 1 part of doubler:
48 + 0 = 48
48/2 = 24

If you are combining the entire bottles a "part" is one ounce:
48 + 0 + 0 + 0 + 0 = 48
48/5 = 9.6

You add the milligrams in each of the parts including the 0s and divide by the number of parts.

I don't have a good eye for size so when I'm combining I'll think I have enough room in the little bottle for 60 drops and I'll put in 40 + 20 (if I'm doing a 2+1 mix.) Then I'll see the little bottle is well less than half full so I'll add another 60 + 30. Or, when I'm adding drops from one, I'll get carried away and put in 47 drops. If the mix is 2+1 that just means I have to add two times 47 (also known as 94) of the other one. As long as I get the ratio of how many parts of A to how many parts of B correct, it works.

If you combine 1 part of e-liquid and 1 part of doubler:
48 + 0 = 48
48/2 = 24

Exactly, which to me means there are 8 parts in the doubler. Holy cow this is confusing. Just when I think I have it right, I go and think on it some more. Lol
 
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