I recently got the IGO-W3 which can use with 1 to 4 coils. Now I use a VAMO V5 which is limited to nothing lower than 1.2 Ohm. Now I'm confused by couple of things such as is the W3 done as parallel or series coils. In other words say I build one coil which shows as 1.5 Ohms. If I added a second coil the same as the first would the Ohms still be 1.5 or 3 Ohms?
Question about coils and a IGO-W3
- Thread starter joecil
- Start date
- th_trl_thread_readers 0
- Status
Depends, you mentioned parallel or series. If you make a parallel setup, each leg reading 1.5Ω, then your circuit would be .75Ω.
Here is the problem is the IGO-W3 coils mounted as they are designed to mount in parallel or series? I'm not sure about that since they share one power post with a separate ground post.
One power post with separate ground posts would be parallel. 4 coils at 2 ohms each would be overall resistance of .5 ohms and 8.4 amps. 4 coils at 1 ohm each would be .25 ohms and around 16 amps. May not be the best setup for your device.
Think of it this way. With each coil you add to a parallel circuit you are doubling the size of the conductor which would half the over all resistance.
Think of it this way. With each coil you add to a parallel circuit you are doubling the size of the conductor which would half the over all resistance.
Last edited:
Just to be sure I understand this, here is an example. I want 1.5 Ohm on my VAMO V5 as the final. So 2 coils @ at with the loops required for .75 Ohms then would be a net of 1.5 Ohms.
If the resistors in parallel are identical, it can be very easy to work out the equivalent resistance. In this case the equivalent resistance of N identical resistors is the resistance of one resistor divided by N, the number of resistors. So, two 40-ohm resistors in parallel are equivalent to one 20-ohm resistor; five 50-ohm resistors in parallel are equivalent to one 10-ohm resistor, etc
If you want your final at 1.5Ω then use two 3Ω in parallel. Both going from ground to positive.
Every coil you add divides over all resistance. 2 coils divedes by 2. 3 coils divides by 3 etc. If you want to end up with over all of 1.5 and 2 coils, each coil would have to be 3 ohms. Clear as mud?
think of it as turning a 30 gauge wire into a 15 gauge wire. As far as your battery knows, that's what your doing.
think of it as turning a 30 gauge wire into a 15 gauge wire. As far as your battery knows, that's what your doing.
Last edited:
Series or stacking resistors end to end.
1.5 + 1.5+ 1.5= 4.5Ω
It's not really what we were talking about. Just wanted to show the difference.
1.5 + 1.5+ 1.5= 4.5Ω
It's not really what we were talking about. Just wanted to show the difference.
Got it guys and thanks, I figured it would save me some wire if I could figure it out first.
- Status
Similar threads
