[FONT="]The Idea/Question[/FONT][/U][/B][B][FONT="]:[/FONT][FONT="]
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[FONT="]How to roughly estimate how many batteries one would need to use through the course of a day in relation to their current or past smoking habit (How many tobacco cigarettes You smoke/smoked). Below is a basic equation that has been formulated to allow an individual to roughly estimate how many batteries that they would need in order to maintain their daily nicotine habit.
Variables:
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[FONT="]At this point, YOU should plug in your own personal values for the variables listed below. basically figure out roughly: your current battery platform metrics, your average draw time and number of tobacco cigarettes you smoke/smoked on a daily average. For example purposes, generic values have been assigned to the listed variables. [/FONT]
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1. Battery: 3.7v 500mAh Li ion Battery (Generic Example)
2. Average Draw Length: 5 sec (varies from person to person)
3. Average Analog Cigarette's Number of Draws: 15 Draws (On the high end)
4. Number of Analog Cigarettes Per Pack: 20 Cigarettes
5. Number of Packs YOU Smoke/ Smoked A Day: 1 Pack (Generic Example)
Battery Basics:
Information Gleaned From Wikipedia:
An ampere-hour or amp-hour (symbol Ah , A·h, A h) is a unit of electric charge, with sub-units milliampere-hour (mAh) and milliampere second (mAs). One ampere-hour is equal to 3,600 coulombs (ampere-seconds), the electric charge transferred by a steady current of one ampere for one hour.[1]
The ampere-hour is frequently used in measurements of electrochemical systems such as electroplating and electrical batteries.
The commonly seen milliampere-hour (mAh or mA·h) is one-thousandth of an ampere-hour (i.e., 3.6 coulombs), and is a technical term for how much electrical charge a particular battery will hold. Small batteries, such as those in laptops and digital cameras, are often rated in milliampere-hours. As an example, digital camera batteries with higher mAh values theoretically last longer without requiring a recharge, allowing one to take more photographs before having to replace the batteries.
Calculation:
1. Generic Battery = 500mAh or 0.5 ampere-hour
2. 1000mAh = 1 hr of steady current
3. 500 ÷ 1000 = 0.5
4. 1hr = 60 min
5. 0.5 x 60 min = 30 min
6. So, 500mAh = 30 min of steady current
7. Average Draw (assuming) = 5 sec
8. 1 min = 60 sec
9. 30 min x 60 = 1800 sec
10. 1800 sec ÷ 5 = 360 Draws
11. Average Analog Cigarette's Number of Draws = 15 Draws (on the high end)
12. 360 Draws ÷ 15 = 24 Analog Cigarettes
13. Number of Analog Cigarettes Per Pack = 20 Cigarettes
14. 24 Analog Cigarettes ÷ 20 = 1.2 Packs of Analog Cigarettes
15. Number of Packs YOU Smoked a Day = 1 (for example)
16. 1.2 Packs of Analog Cigarettes ÷ 1 = 1.2 Days of Regular Smoking
Conclusion:
If we lived in a perfect world, with no other variables present a generic battery that is actually registered at 500mAh "could" last a one pack per day smoker/ex-smoker, 1.2 days. Basically, one generic 500mAh battery could float a one pack per day smoker/ex-smoker an entire day, for purposes of vaping. In reality, with variables like: heat, incorrectly marked battery mAh, length of draw, atomizer efficiency, atomizer Ohm, battery voltage drop off, material resistance, electronic personal vaporizer design, battery age, variable discharge rates, battery chemistry, personal vaping/smoking habits, ad nauseum, etc., an average vaper should expect to go through at least two 500mAh batteries in the course of a single day of average vaping. Again, this is a rough way to estimate one's own battery necessities, not an etched in stone fact. It is always best to assume that you need more batteries than what the above equation generates, because of the other variables that have been discussed. I hope that this has been informative and will be a useful tool for vapers to base their battery purchases off of.[/FONT]
