~The Billet BoX~

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Kataphraktos

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That's right...that was a typo on kata's part...

No, it was not.

Example:

2 ohm coil @ 4 volts = 2 amps.

3 ohm coil @ 5 volts = 1.667 amps.

Since amperage is a measure of electricity passing through a discrete spatial point per time, the fewer the amps, the longer your battery should last, given a fixed delta between resistance and voltage. The delta in battery life between these two setups should be about 10%. Will you notice this delta? Probably not.

At 3 ohms, even at the max BB voltage of 5.5 volts, you would only be chugging along at 1.83 amps, still more efficient than 2ohms.

Rule of thumb: higher voltage reduces current. Lower current = more battery life.

When did I become Sheldon Cooper?
 

Kataphraktos

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I ordered a diver from atmistique last week, but there was a mistake apparently made on their end when calculating the price. They emailed me saying I would need to send them an extra 3 euros. I didn't have time to deal with it right then and they cancelled my order and refunded my money the next day. Today I discovered they were in stock at avid vapor so I placed an order with them instead. It will be interesting to see if they arrive before yours.

To be honest, I'm a little skeptical about how well they work. I have gotten so spoiled by the flavor provided by my russian that the cartos in my BB just aren't doing it for me right now so I'm hoping to fix that situation with the diver. I sure hope it works because I'm hating the ugliness of my current setup and love the practicality of the BB.

Come to the Diver thread if you have any issues.

FWIW, last night I put my money where my big fat mouth is. I spent an obscene amount of money buying two more Divers and two more Scuba tanks for my new Provari Stealth Mini, to make an all-black Delrin setup and a gold-plated setup. And when the BB tanks are back in stock, I will be buying yet another 1-2 Divers and 1-2 BB tanks so I can swap out juices.

Flavor out of Svoemesto-style attys and carto-style attys is not really comparable. Apples and oranges. I used to have a polished KF 3.1ES and a KFL. Now, Pluid SUCKS in a Diver IMO, but it was pretty good in a Kayfun. Bakery flavors are pretty good in a Kayfun, but outstanding in a Diver. YMMV.
 

ThreeDJ16

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No, it was not.

Example:

2 ohm coil @ 4 volts = 2 amps.

3 ohm coil @ 5 volts = 1.667 amps.

Since amperage is a measure of electricity passing through a discrete spatial point per time, the fewer the amps, the longer your battery should last, given a fixed delta between resistance and voltage. The delta in battery life between these two setups should be about 10%. Will you notice this delta? Probably not.

At 3 ohms, even at the max BB voltage of 5.5 volts, you would only be chugging along at 1.83 amps, still more efficient than 2ohms.

Rule of thumb: higher voltage reduces current. Lower current = more battery life.

When did I become Sheldon Cooper?

Mmmm, don't break out the propeller hat quite yet Mr. Cooper. You're forgetting the mistress that can't be dismissed who is power. Power is the ultimate determining factor for battery life.

Example:

2 ohm coil @ 4 volts = 2 amps. = 8 watts

3 ohm coil @ 5 volts = 1.667 amps. = 8.3333 watts

You can't get more power using less battery.

Forgot this one - 3 ohm @ 5.5 = 1.833 amp = 10.08 watts = way more power
 
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Kataphraktos

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Mmmm, don't break out the propeller hat quite yet Mr. Cooper. You're forgetting the mistress that can't be dismissed who is power. Power is the ultimate determining factor for battery life.

Example:

2 ohm coil @ 4 volts = 2 amps. = 8 watts

3 ohm coil @ 5 volts = 1.667 amps. = 8.3333 watts

You can't get more power using less battery.

Forgot this one - 3 ohm @ 5.5 = 1.833 amp = 10.08 watts = way more power

Look at your numbers.

You are getting 8 watts for 2 amps, or 8.3333 watts for 1.667 amps. You are getting 0.3333 watts MORE for 0.3333 amps LESS.

Here's another way to understand. Use the rapidtable converter here, and try setting amps to 2.0 (so fixed battery life). Now calculate ohms and watts with voltage at 4.0 and at 5.0.

At 4 volts, you would use a 2ohm coil to get 8 Watts of power. At 5 volts, you would use a 2.5 ohm coil to get 10 Watts of power. Same battery life, more power.

Why? Because the relationship between resistance and power is linear, but that between power and current is square.

So the obvious question is, why don't we just set everything to an insanely high voltage, and have extremely efficient power consumption in everything? One word: danger.

In the US, we use 110V in the grid. In Europe, it's 220v. The chances of surviving direct contact with a European wall socket are lower than those in the US.
 

ThreeDJ16

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A little more perspective on what we are using here. Wiki states it way better than I would: "An ampere-hour is not a unit of energy. In a battery system, for example, accurate calculation of the energy delivered requires integration of the power delivered (product of instantaneous voltage and instantaneous current) over the discharge interval."

You don't get anything for nothing. We are not getting....we are using!

So with your logic a 100w bulb uses less energy than a 60w.....I want to live in your world.
 
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Kataphraktos

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In the US, we use 110V in the grid. In Europe, it's 220v. The chances of surviving direct contact with a European wall socket are lower than those in the US.

And I've been blessed with having closed circuits at both 110v and 220v in my life, and lived to tell the tale.
 

Kataphraktos

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A little more perspective on what we are using here. Wiki states it way better than I would: "An ampere-hour is not a unit of energy. In a battery system, for example, accurate calculation of the energy delivered requires integration of the power delivered (product of instantaneous voltage and instantaneous current) over the discharge interval."

You don't get anything for nothing. We are not getting....we are using!

So with your logic a 100w bulb uses less energy than a 60w.....I want to live in your world.

That's ampere-hour, which is the amperes over a given unit of time.

I found a great article on this:

HowStuffWorks "What are amps, watts, volts and ohms?"
 

Kataphraktos

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So with your logic a 100w bulb uses less energy than a 60w.....I want to live in your world.

It is not about energy, it is about efficiency. While you may be getting more battery life for the same power output, you are also in all likelihood reducing the total life expectancy of the battery, which means you will have to replace the batteries more often.

A single PC can do the same work that a floor of accountants used to do with pen and paper. But those accountants lasted for decades if cared for properly. That PC will need replacing inside of 5 years, max.
 

Kataphraktos

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ThreeDJ16

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It is not about energy, it is about efficiency. While you may be getting more battery life for the same power output, you are also in all likelihood reducing the total life expectancy of the battery, which means you will have to replace the batteries more often.

A single PC can do the same work that a floor of accountants used to do with pen and paper. But those accountants lasted for decades if cared for properly. That PC will need replacing inside of 5 years, max.

Now you're trying to change your point completely. Your first post was totally geared towards how long from having to put in a fresh set of batteries (indicating one vape session). Now you are trying to say it is before you toss a battery. Make up your mind. Sure you are not a lawyer instead of a wall street douche? And FYI, that point is total BS. The higher wattage is discharging at a rate greater than the lower wattage. Yes, even at a lower current. Current is only one side of the equation, as I said discharge (which is a unit of charge, hence a battery). Discharging a battery faster would result in it's death sooner.
 

ThreeDJ16

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Ampere is electrical current. It is the rate of discharge.

Ampere-hour is electrical charge. it is the total discharge available in your battery.

No!

"An ampere-hour is not a unit of energy. In a battery system, for example, accurate calculation of the energy delivered requires integration of the power delivered (product of instantaneous voltage and instantaneous current) over the discharge interval."

Can't have one without the other dude which is power (watts)!
 

DPLongo22

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And for the carto folks in here, I also discovered something that I found pretty interesting this weekend. It may be covered in one of these 855 pages, but I might have missed in while perusing through.

Last weekend I swapped cartos in my 2nd tank, then filled it. I didn't put in into the BB, and circumstances resulted in it sitting for a full week. Yesterday morning I did the reverse. The difference in flavor, from just putting it and and letting it sit for a few minutes, was literally amazing.

Moving forward, this will be my routine, whenever swapping cartos. Replace the entire tank with the one that's had the carto soaking, and let the new carto sit until I need to swap again.

It's not Sheldonesque, by any stretch, but it's knowledge that will serve me quite well.

And we now resume you to your regularly scheduled Mensa meeting. ;)
 

Akdare

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With all due respect to Kata & Drunk:

Drunk is correct...it is about power, and the original question was about longer battery life. If we want to talk about how long a particular battery will "live"; i.e., how many times we can charge it up and it still reach it's full potential, that has more to do with the battery chemistry...

- AK Dare, B.S.E.E., M.B.A., C.F.P., LMNOP.
 

Kataphraktos

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Now you're trying to change your point completely. Your first post was totally geared towards how long from having to put in a fresh set of batteries (indicating one vape session). Now you are trying to say it is before you toss a battery. Make up your mind. Sure you are not a lawyer instead of a wall street douche? And FYI, that point is total BS. The higher wattage is discharging at a rate greater than the lower wattage. Yes, even at a lower current. Current is only one side of the equation, as I said discharge (which is a unit of charge, hence a battery). Discharging a battery faster would result in it's death sooner.

No, I was adding to my point. When you increase efficiency, you also reduce the total life available out of that battery.

But let's go back to your example:

Example:

2 ohm coil @ 4 volts = 2 amps. = 8 watts

3 ohm coil @ 5 volts = 1.667 amps. = 8.3333 watts

You can't get more power using less battery.

Forgot this one - 3 ohm @ 5.5 = 1.833 amp = 10.08 watts = way more power

You just said over and over that you cannot get more power without draining your batteries faster.

Yet your own example, quoted here, shows a battery discharging at 1.667 amps with 8.333 watts power output, whereas your lower-voltage setup gives only 8 watts at 2 amps (which is a higher discharge rate).

Then you increase the power dramatically to over 10 watts, but still didn't hit the discharge rate of your original 2 ohm/8 watt setup.

But, you know what, I'm being told via PM that I'm wrong here, so ignore everything I've said here, and all the articles I've linked, and go with using ampere-hour as a unit of discharge rate. I gain nothing from this or any other debate here, other than being (once again) told to shut up.
 
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