Vtc mini

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VNeil

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How accurate is the current on this? I thought on a regulated mod resistance was irrelevant? So 75w/4.2v=17.8a

That is correct

But on my 0.6 coil at 75 w it's 11.6a
My 0.19 coil at 75w is 23a

What am I missing here lol

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The 17.8A is the current through the battery, assuming it really stays at 4.2V at that load (probably doesn't but let's keep things simple and assume it does).

The 11.6A on your 0.6R coil is the current through the coil. The mod has stepped the voltage up or down from 4.2V in order to deliver that power to that coil. In this case it should be reading about 75/11.6 = 6.4V

Same with the 0.19R coil. 75/23 = 3.26V

If you multiply the current the mod tells you, by the indicated voltage, then you should end up with 75W.
 

Topwater Elvis

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You are confusing regulated power device vs mechanical power device calculations & amp demands.

Using a regulated power device as battery voltage drops amp draw/drain from the battery has to increase to supply the power the chip demands.
The battery doesn't stay at 4.2v for very long at all.
At your power devices low voltage cutoff the amp drain/demand will be highest, at 4.2 volts it will be lowest.

Regulated power device, not figuring in chip inefficiency.
As battery voltage decreases amp demand increases.
75w / 4.2v = 17.85a
75w / 3.5v = 21.42
75w / 3.2v = 23.43a

Mechanical power device;
At 4.2v the amp demand will be the highest,
As the voltage diminishes.
4.2v / .19Ω = 22.1a, 92.8w
3.77v / .19Ω = 19.86a, 75w
3.7v / .19Ω = 19.4a, 72w
3.5v / .19Ω = 18.4a, 64.4w
 
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