OK. So no hard science then.
Thanks for the unsolicited opinions on what I should do with my juice. :/
What would you like? A decay rate algorithm? And exponential decay model? Because there isn't.
Here, let's try. Our base population model: N(t) = Ne^(kt) Here we are looking for a decay model so k will be negative making our model N(t) = Ne^(-kt). We know someone may have lost 1 mg of 100 mg nicotine juice in 5 years. Let's be generous and say it was 1mg/mL in lost potency which it was not, I just want to show you how long this would take even with that much lost. That means after 5 years we still have 99% of our potency left. No matter the starting amount we can set up our model like this: 0.99N = Ne^(k(5)) The N's can cancel and we are left with 0.99 = e^(k(5)) Taking the natural log of each side we get: ln(0.99) = 5k and finally our decay rate: k = ln(0.99)/5 ~ -0.00201007 We now have out complete model with a decay rate: N(t) = Ne^(-0.00201007t) with t in years. Let's figure out the half-life if nicotine with this model.
0.5N = Ne^(-0.00201007t) canceling the N's and taking the natural log of each side we get: ln(0.5) = -0.00201007t therefor the time for even half of any amount of nicotine to remain would be: t = ln(0.5)/(-0.00201007) ~ 344.84 Years.
This is assuming nicotine decays at an exponential rate. It could be linear, logistic, who knows.
This also assumes that whatever device this person used to measure nicotine was any sort of accurate and precise.
The point being, there is no hard science of the decay rate of nicotine in e-juice. Just try a google search, nothing but pure speculation.
I wish you good luck.