Does more resistance make a coil heat up faster or slower at the same wattage?
Dan
Dan
At a set wattage what size coil heats faster.
- Thread starter DigitalVI
- Start date
- th_trl_thread_readers 0
- Status
Lower resistance would heat up faster but then again, a lot has to do with gauge. Thicker gauge, lower gauge, has less resistance per mm, inch, foot but takes longer to heat up. Thinner, higher gauge wire has higher resistance but heats up quicker
Yeah, I too think it's about wire mass. Any particular gauge, the longer the wire (more resistance, btw), the longer it takes. And any given length of wire, the fatter it is, the longer it will take to heat. (It's really only less resistance cause there's more of it . .. . width wise)
Thanks for that. So a 1.5 ohm 32ga would heat faster than a 1.5 28 ga. Would this make a difference in vapor production?
Yes, the resistance has nothing to do with how fast it heats, as long as the wattage is constant. It's mass that counts. Or more accurately, the heat capacity of the material used.
Thinner gauges also have a higher surface-to-mass ratio. That will help heating the juice faster, as opposed to heating the coil faster.
Thinner gauges also have a higher surface-to-mass ratio. That will help heating the juice faster, as opposed to heating the coil faster.
Last edited:
Wattage constant, the 32 gauge gets hotter faster. The difference is that at 8 watts, the 32 would produce more vapor due to the much lower mass. At 15 watts, the 28 gauge coil would probably vape much better than the previous coil, which would simply be burning juice or popping itself at that wattage. It's all about wattage related to mass creating temperature utilizing surface area. Someone really needs to define the whole system mathematically...
Hmmmm, you got me thinking ... what would the input parameters be, and which output parameters would be the most useful? Once we've got that figured out, making a calculator for it should only be a matter of typing some equations in javascript.
We'd need to get all the equations, make some assumptions on what to neglect in terms of heat transfer, and figure out how to estimate some constants. I will do some more thinking and research on it and report back later.
This might be a good starting point: http://www.e-cigarette-forum.com/forum/new-members-forum/533569-where-my-clouds-2.html#post12374133
It doesn't do heat transfer, but it does calculate watts per square mm.
It doesn't do heat transfer, but it does calculate watts per square mm.
- Status
