Can someone help me with ohms/mah/volts?

[Sinlak]

Ok so I was trying to figure how roughly how long 1200 mah would last me and I was hunting for some calculations that might solve this, couldnt find one. But I did find this

Ohm's Law: V = I*R, with V is voltage (volts), I is current (amps), and R is resistance (Ohms).

How dose this equation help me figure stuff out? Like the maximum volts my atty can handle?

I just want some equations to help me solve stuff because im curious and enjoy math..thx (Sorry if in wrong area)

 

[BardicDruid]

Equations won't help much, depends on what type of batt and the resistance of the atty or carto. For eGo/Riva style batts LR attys & cartos wear them out quick, where the mods that use AA type batts are better for them. The best batts are the AW and for LR's the AW IMR high drain works the best.

 

[Sinlak]

I mean I know what works and what wont work and the ohms of my stuff and the volts of my bats, im just curious whats the equation to figure stuff out like for instance

if I have a 1.8ohm atty, a 3.7volt batt and 1600mah, And lets say I take a hit every..10 minutes and each hit lasts 3 seconds, how long will the battery last? how much MAH is used per second of my firing the device..

Also what equation will help you determine the maximum volts/minimum volts X ohms can handle, Would I use V=I*R? what if I dont know the amps? is it R/V=I?

 

[XKingXGregX]

Its how much resistance or voltage amount the atomizer can withstand It resists the current low resistance will allow more voltage. High ohms will allow less but allow u to add more amps. u wouldnt want to use high ohms in low voltage it wont heat up enough and u dont wanna use low ohms in hv it will pop because voltage travels through it with less resistance. Ohms is refered to as the resistance the atomizer is good for. 1.5 is low resistance not to be used at higher voltage. standard is around 2 ohms which I perfer at 5ish volts. 3 ohms and up would be good for high voltage I may be wrong about exact ohm ratings but im just giving examplea of how it would work forget ohms law thats like electrician equation used for finding the missing variable between voltage amps or resistance by multipling or dividing any two youd calculate the third variable its simple but I need the chart to remember which geys divided or multipled

 

[MickeyRat]

I doubt you're going to get anything accurate by guessing how many hits you take per hour and trying to get to MAHs. Theres a lot a variation in how vendors pad their MAH ratings and they aren't independently verified as far as I know. So, you probably really don't know your true MAH rating.

This page will help for ohms law calculations but, there's no formula that will relate back to MAH.

They can be useful to get relative power usage at different ohms. For instance, if I like a 2.5 ohm atomizer at 4.3V, what atomizer am I likely to like at 3.7V. Get the power calculations pretty close and you're there. You still need to try it, it's not going to be exactly the same.

 

[Sinlak]

I'm aware it won't be acurate. I was just curious how to calculate it asuming your data is accurate. Even tho its now, so asume when the battery says 1600mah that its a true statement.
I just asumed that for ever second of a battery firing at 3.7 volts into 1.5 ohms there would be a way to figure the amt of mah used asuming all your numbers are true and constant

Thanks for the input and the link ill check it out.

Sent from my DROID2 GLOBAL using Tapatalk

 

[Rocketman]

Would I use V=I*R? what if I dont know the amps? is it R/V=I?

No, it's V/R=I.
Try playing with the math. Volts, AMPS and OHMS. 1000ma = 1 amp. mah for Li-ion cells (most lie about capacity) is milliamp X hours for an average voltage of 3.7 volts. Each puff uses thousands of milliamp seconds

Use 3.7 (average) volts, seconds per puff, number of puffs per hour for time, and 3.7V / 1.8 ohms.

That's all the electrical units and math you will need for a rough calculation. But, as others have said, it's not a lot of use in real practice, but it is a good math exercise. I like math too

 

[WillyB]

I'm aware it won't be acurate. I was just curious how to calculate it asuming your data is accurate. Even tho its now, so asume when the battery says 1600mah that its a true statement.
I just asumed that for ever second of a battery firing at 3.7 volts into 1.5 ohms there would be a way to figure the amt of mah used asuming all your numbers are true and constant

No real way to do it and folks 'hours', 'days' etc are all over the place.

Here's a chart/test.

This UF14500 had a true mAh of 592 @ .8A discharge. It took 44 min to drain.

Maybe you can read somthing into this that will apply in your case.