Cross compatibility

[roycrt]

I read a lot of posts where users bought one part from one supplier and another from another supplier. Besides always buying from the same supplier. How can you ensure cross compatibility? There does not seem to be a standard across the suppliers...

 

[Stownz]

Adapters! PV Adapters

But for the most part, the most popular connection being made these days is the 510.

 

[carpedebass]

Yea, you need to find out what connection you have...as Stowns alluded to. 510 threaded stuff will work with 510, 901, 810, etc will need an adapter or a similar threaded device.

 

[JustaGuy]

Try to keep it simple, pick either the 510 or 808 most popular thread model and get only parts for that model. The only complications are tank models that may not work with other parts, plus you need to watch out for batt & atty/carto ohm compatibility. If you stay middle of the road on that, it'll be easier. Here's a reference table: Why resistance and voltage is important!

 

[sln88]

this is one thing that confuses me. if I have an 1100 mah ego battery, can I charge it on a charger that came with a 650 mah battery?

 

[JustaGuy]

this is one thing that confuses me. if I have an 1100 mah ego battery, can I charge it on a charger that came with a 650 mah battery?

I believe you can. Madvapes and Liberty Flights only sell one 420 ma eGo USB charger. You can't use it on mini 510 batts and it will take a little longer to charge the 1100 mAh.

 

[dormouse]

In general yes. You can charge all real Joye/Janty Ego batteries and Riva 510 batteries and all correct Ego clone batteries on the same charger. HOWEVER there is at least one %*&#^*# Ego clone that is reverse electrical polarity called Ego-J or something and that would fry on a normal Ego battery charger. So I warn people not to buy any random clones unless they know it is a good model and correct polarity and in all ways compatible with the real thing. If you are buying random stuff from China or mystery brand Ego batteries then it's a crapshoot.

What you cannot charge on an Ego or other big-battery 510 charger: 901 threaded big-battery models nor any other-threaded models and do NOT try an adapter. Adapters are meant for atomizers and cartomizers which don't care about polarity. Never use an adapter to try to use another threading's charger. Also, you cannot charge slim ecigs on a big-battery model's charger - it will damage them. The big battery model charger put out around 420mA and the slim model chargers put out around 150-220mA.

 

[JustaGuy]

Is there anything dormouse doesn't know?

 

[carpedebass]

Is there anything dormouse doesn't know?

You are given a triangle that has sides of 66cm, 73cm, and 94cm. One of the angles is right-angled (meaning that it is possible by trial and error to calculate what each of the angles are). Inside this triangle is a square, so that three corners are in contact with the lines bounding the triangle. One of the sides or the square, which we shall now dub z, is also tangent to a circle, with a radius such that the centre of the circle lies along the side of the triangle with length 73cm. You are also given a regular octagon, which you are told is the same area as the total are of the circle and triangle if they are taken together (i.e. the overlapping area is not counted twice), and one side of this octagon forms another side of equal length belonging to a second square. The area of this square is dubbed x.


Give the value, to three significant figures, of x.

An isosceles triangle is drawn so that it has the same area as the above square (i.e. x), and with two sides that are equal to the square root of x (henceforth dubbed y). What is the length of the third side?

If successful...Prove that the triangle above exists.

 

[4mehealth]

This is a multi-part question that isn't clear. That or I skimmed it.

Triangle 1 with 3 different lengths is not an isosceles triangle.

Now gimme a cookile.

 

[JustaGuy]

You are given a triangle that has sides of 66cm, 73cm, and 94cm. One of the angles is right-angled (meaning that it is possible by trial and error to calculate what each of the angles are). Inside this triangle is a square, so that three corners are in contact with the lines bounding the triangle. One of the sides or the square, which we shall now dub z, is also tangent to a circle, with a radius such that the centre of the circle lies along the side of the triangle with length 73cm. You are also given a regular octagon, which you are told is the same area as the total are of the circle and triangle if they are taken together (i.e. the overlapping area is not counted twice), and one side of this octagon forms another side of equal length belonging to a second square. The area of this square is dubbed x.


Give the value, to three significant figures, of x.

An isosceles triangle is drawn so that it has the same area as the above square (i.e. x), and with two sides that are equal to the square root of x (henceforth dubbed y). What is the length of the third side?

If successful...Prove that the triangle above exists.

All I know is A suared x B squared = C squared. Lots of squares...and dormouse knows vaping.

 

[carpedebass]

This is a multi-part question that isn't clear. That or I skimmed it.

Triangle 1 with 3 different lengths is not an isosceles triangle.

Now gimme a cookile.

ROFL! OK, one "cookile" coming right up...whatever that is...

 

[DaveP]

You are given a triangle that has sides of 66cm, 73cm, and 94cm. One of the angles is right-angled (meaning that it is possible by trial and error to calculate what each of the angles are). Inside this triangle is a square, so that three corners are in contact with the lines bounding the triangle. One of the sides or the square, which we shall now dub z, is also tangent to a circle, with a radius such that the centre of the circle lies along the side of the triangle with length 73cm. You are also given a regular octagon, which you are told is the same area as the total are of the circle and triangle if they are taken together (i.e. the overlapping area is not counted twice), and one side of this octagon forms another side of equal length belonging to a second square. The area of this square is dubbed x.


Give the value, to three significant figures, of x.

An isosceles triangle is drawn so that it has the same area as the above square (i.e. x), and with two sides that are equal to the square root of x (henceforth dubbed y). What is the length of the third side?

If successful...Prove that the triangle above exists.

The answer is 42, according to Monty Python. This is further proven by the fact that Ice Cream has no bones. This fact was also stated to be true by Brother Dave Gardner.

 

[carpedebass]

All I know is A suared x B squared = C squared. Lots of squares...and dormouse knows vaping.

The only one of those letters that comes anywhere near to being a square is B. Shows ya' what I know...

 

[carpedebass]

The answer is 42, according to Monty Python. This is further proven by the fact that Ice Cream has no bones.

YES!! A correct answer...I think...

 

[JustaGuy]

If successful...Prove that the triangle above exists.

Coming from the school of empiricism and existentialism, if I the triangle and the noggin hurts, it exists!

 

[carpedebass]

Coming from the school of empiricism and existentialism, if I the triangle and the noggin hurts, it exists!

Hey, it works for the FDA...why not all of us?!?

 

[dormouse]

The triangle does not exist (I am just guessing)

 

[carpedebass]

The triangle does not exist (I am just guessing)

OK Mrs (Ms?) Smartypants...prove that it doesn't exist...no guessing. C'mon...you're up to this!!

 

[dormouse]

A triangle with sides 66cm, 73cm, and 94cm can't have a right angle. To be a right triangle, the 94 cm side would be 98.412398 cm.

(I am just copying this off the web)