Hypothetical

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Stosh

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Hypothetically if your electronics are 100% efficient, they would last exactly the same time.

You're running both at 10 watts, and watts are the result of a combination of voltage and current. If one goes up while the other goes down, it balances out the draw on the battery charge.

Most mods are running over 90% efficiency so you might see a difference of a few minutes, but not a large difference.
 

BlkWolfMidnight

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Aaaand,
Happy Holliday's to all, ok, so given that technically if you duel coil the mod the two will balance out (Think of two glasses connected by a hose, they will find level).
Reason they don't heat evenly is because of the Ohm's that you are presenting, the voltage will be set to the highest ohm coil (I believe, haven't tested that myself).
As for longevity if single coil the higher ohm will last longer only if the guage of the wire (amps) is also higher, lower guage wire wrapped more times will drain a battery faster.
Lots of "If's" in this one really, best thing to do is bust out some scientific equipment and test it. I'm more then sure that it would give you the answer that way. Other then that it is, just at Theory.
Happy holidays everyone :)
 

Don Robertson

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The comparison is only valid at the starting voltage. Use diminishes the voltage and the "watts/ amps" change accordingly making it difficult to determine the longevity of either. The voltage would likely not drop to the lower number shown, yet even if the starting voltage is increased the resulting voltage will drop and the "watts / amps" will still change proportionally Or, so says my senile mind; others may disagree, but a change in one parameter always produces a change in the other two - with the resistance (load) remaining constant.

Resistance (Ohms) -- 1.0 ............................... 2.0
Voltage (Volts) --------- 3.2 .............................. 4.5
Power (Watts)---------- 10.24........................... 10.125 <------------ Is only going to be accurate at the starting voltage. As voltage drops the values change significantly.
Current (Amps)--------- 3.2 ............................ 2.25

Resistance (Ohms) -- 1.0 ............................... 2.0 <------------ If Resistance in the coil remains stable (it should unless you change the coil)
Voltage (Volts) --------- 2.0 .............................. 1.0<------------- But voltage drops (it will with use)
Power (Watts)---------- 4.0 ...............................0.5 <------------ Wattage drops
Current (Amps)--------- 2.0 .............................. 0.5<------------ Current drops

The solution? Buy the best battery available with the highest watt-hours available and run it until it is at the lowest recommended voltage (preferably higher) and re-charge.

From Senility Central ..... Old Man Donnie
 

Stosh

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.....The solution? Buy the best battery available with the highest watt-hours available and run it until it is at the lowest recommended voltage (preferably higher) and re-charge.

From Senility Central ..... Old Man Donnie

Absolutely!! There are many variables to consider, mech vs. regulated at 10 watts, the efficiency of any circuitry or resistance of a mech, the gauge of your kanthral and how much metal does the 10 watts have to heat, etc.....

For the OP's question, higher volts or higher amps at 10 watts....both drain the watt hours the same.
 

Ryedan

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Let there be two coils, one at 2 ohms and the other at 1, and let them each be fired at 10 watts.

The comparison is only valid at the starting voltage. Use diminishes the voltage and the "watts/ amps" change accordingly making it difficult to determine the longevity of either.

Don, if you're using a variable wattage device set to 10 watts, the watts stay at 10 until the device is shut down because of low battery voltage. You are absolutely correct if the device is a mechanical mod though :thumb:
 
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