Is it Safe?

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KenD

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with regulated mods, you don't need to take amps drawn into consideration; the mod does that for you....it's not as simple as x watts equals y amps as it is with a mech mod.
You most certainly need to consider the amps. Resistance doesn't factor into the amp draw though. This is how you calculate the amp draw:

Watts / battery cutoff voltage (multiply by the number of batteries in a series mod) = amps. Divide the amps by .9 to account for device inefficiency.

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speedy_r6

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Triade is a 3 battery regulated mod with a cutoff of likely 3.2v/cell. Let's use 3 for safety. They are 20a batteries. That gives us 3 batteries times 20 amps, or 60 amps total. Multiply that by the cutoff voltage of 3 volts, and you get 180 watts. Subtract 10%(18 watts) and it tells you 162 would be clearly in the safe zone for three 20a batteries.

You could probably get away with 180w safely if you are switching them out when they hit half their voltage. Since we actually knocked off a fair amount early on(3v vs 3.2v), you would probably be safe through the whole charge at 180w, but cutting it pretty thin. It all comes down to how much safety margin you want to have.

If they were 25a batteries, that gives us 75a*3w, or 225 watts. Knock 10% off(22.5w) and you get 202.5w being safe with 25a batteries.
 
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bwh79

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with regulated mods, you don't need to take amps drawn into consideration; the mod does that for you....it's not as simple as x watts equals y amps as it is with a mech mod.
Actually you have it exactly backwards. It's the resistance that doesn't factor into battery safety with regulated devices. Also, on those devices that show an "amps" value on the display, that figure is the (meaningless) output amps delivered to the atomizer and not the (useful to know) input amps being drawn from the battery/ies which could lead to your confusion as that particular amps value does not need to be taken into consideration.

...but it very much is as simple as "x watts equals y amps," at least assuming constant battery voltage (and you should assume low-voltage cutoff of 3.0v (per battery) under load, for safety calculations, unless you know the actual cutoff point and power efficiency of the device in question.) For reference, "y" = "x/3" so 60 (x=60) watts, at 3.0v cutoff, equals 20 (y= 60/3) amps. Multi-battery setups increase this wattage "speed limit," either by doubling/tripling the battery voltage (wired in series) or by "sharing" the amp load between each cell (wired in parallel); the calculations are different but the end result is the same: stay under 60 watts, per battery -- or (amp rating x cutoff volts) if you're not using 20A batteries, or a device that cuts off at other than 3.0 volts -- and you'll be fine.
 
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brittianm

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Triade is a 3 battery regulated mod with a cutoff of likely 3.2v/cell. Let's use 3 for safety. They are 20a batteries. That gives us 3 batteries times 20 amps, or 60 amps total. Multiply that by the cutoff voltage of 3 volts, and you get 180 watts. Subtract 10%(18 watts) and it tells you 162 would be clearly in the safe zone for three 20a batteries.

You could probably get away with 180w safely if you are switching them out when they hit half their voltage. Since we actually knocked off a fair amount early on(3v vs 3.2v), you would probably be safe through the whole charge at 180w, but cutting it pretty thin. It all comes down to how much safety margin you want to have.

If they were 25a batteries, that gives us 75a*3w, or 225 watts. Knock 10% off(22.5w) and you get 202.5w being safe with 25a batteries.
It is a series mod, so the amps would not be tripled.
 

speedy_r6

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It is a series mod, so the amps would not be tripled.

It is a regulated mod, so it doesn't really matter if they are series or parallel.

Three 20a cells in series giving 9v(assuming 3v/cell cutoff) gives you 9v times 20 amps, or 180 watts before you take off the 10% for mod inefficiency, bringing you to 162w safely at cutoff.

Three 20a cells in parallel giving you 3v times 60 amps is still the same 180 watts before the 10% mod inefficiency, resulting in the same 162w safely at cutoff.

With a regulated mod, you can do it either way. You have 3 cells that give 3 volts(assumed cutoff) at 20 amps. 3*3*20=180

It doesn't matter if you read it as (3*3v)*20a or 3v*(3*20a). The first way would be in series, the second in parallel. Either way, they give you the same answer. 3*3*20 will always be 180.
 
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Eskie

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One fudge factor here is a DNA 200/250 board is supposedly (always hedge with manufacturers specs) 97% efficient. IRL, I'd call it 95%. 180W on a DNA board with 3 25Rs should be fine. It's one of the very few boards I would trust with high wattage use. I probably wouldn't wait until the battery indicator is at flat zero before swapping out. No need to push things that far. I'm not even a high wattage user, but still swap out batteries at about 1/4 full as it is.
 
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