More surface area = more vapor?

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Sonofamitch

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May 3, 2011
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Downingtown, PA
Hey guys, I've been reading up a LOT recently on a BUNCH of different setups. I know that there are 3 ways to get more vapor.
1. Higher voltage = more heat = more vapor
2. Lower Resistance = more heat = more vapor
3. Use more VG (at the expense of throat hit though right?)

I was thinking...what if you went with double the voltage and double the resistance. That way you would be getting the same amount of heat...but over a bigger surface area on the coil. which in theory should vaporize even more juice right? Is that the point of the high resistance (high voltage) atty's? more surface area for the juice to vaporize?
 

Sonofamitch

Full Member
May 3, 2011
11
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34
Downingtown, PA
It doesn't have to be higher heat per say, same temp just applied to two seperate coils wrapped around two separate wicks coming from two separate batteries. essentially like combining two batteries and two ce2's into one device. Higher heat is what I DON'T want. I'm trying to get MORE vapor not HOTTER vapor. granted the device will use a lot more power (double to be exact) which means you will have to either suffer shorter battery life, a much BIGGER battery or a combination of the two. I'm thinking...I already have a 4.8v 2300mah NiMH mod box that I made...so for something like this I would want 2, 3.0 ohm coils and it would still outlast my epower with a 2.4-2.6 ohm fluxomizer on it but with twice the vapor production.
 
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