So I'm brand new to the dripping scene, I have a question about dual coils, I know the resistance is halved, but what about the amps, do they double with the two coils or does it completely depend on the total resistance of both coils? In other words, if I run a .3 ohm single coil on my RDA, will a .3 ohm dual coil use the same amount of amps? Sorry if this is noobie.
Need RDA Help!
- Thread starter XxiI_ARES_IixX
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Yes, if you double the number of coils, then the resistance gets cut in half and then the current will double.
If we're talking about a total resistance of .3 ohms then it's the same whether that resistance comes from one coil or two.
If it's two coils that EACH measure .3 ohms then it's a different ballgame.
If it's two coils that EACH measure .3 ohms then it's a different ballgame.
Whatever both coils measure out to be will be the resistance and the amps required to power it will be whatever it would be. The battery doesn't know why there is resistance or what's causing it.
So I calculate the draw in amps from the total final resistance of the two coils, so two 1ohm coils give me a .5 resistance, but the amps it draws is only what a .5 ohm coil would draw? So I can run a .8 ohm dual coil setup on my 12 amp battery?
A cool fire 4, I talked to the guys at my local vape shop and they said I could but they recommend not going below a .8, however I don't want to damage my battery or myself.
To ease your mind - the electrical circuit is completed by what you can think of as the RDA as a whole. You have however many or few coils installed between the positive/negative posts of your atty - that total or "net" resistance is taken as a whole when it comes to amp draw from your battery. This is true whether you have dual matching coils, quad matching coils, or even if you have coils of different resistances installed (yeah, don't do that, it won't vape well, but you see the point I'm making). There's a lot more to it than that, but that's the simplest I can put what you need to know
I hate to call you out, Axiom, but but gotta so as not to mess up the OP. This quoted post isn't right. Again: Total resistance 0.3 ohm will always be total resistance 0.3 ohm. As an example, a dual coil atty that meters to 0.3 will, at 4.2 volts, pull 14 amps; a quad coil at total 0.3, at the same 4.2V, still 14A; a single 0.3, 4.2V, 14A
So, a .8 dual coil at 25 watts or 4.4 volts will only be 5.59 amps regardless of how many coils I have? All I'm asking is, does having multiple coils increase the amps, decrease the amps or use the same amps?
Let me try to clear it up.
If you made one .3 ohm coil on a fresh 4.2 volt battery, you would be pulling 14 amps from your battery , and using 58.8 watts of power.
If you added a second .3 ohm coil to the atomizer.. you would be using a .15 ohm setup You would be pulling 28 amps from your battery using 117.6 watts of power. What happens to that power in the dual coil setup? Well, You would still be pulling the same amps from your battery. Each coil will still receive 4.2 volts, but each coil will get 58.8 watts.
I personally like to use watts as a general gauge of what I want to build. I prefer about 20 watts going through 26 gauge wire, and 15 watts going through 28 gauge wire. If I use a dual coil setup, that means I have to take the two coils into consideration. Right now, I am vaping on a dual coil fogger tank. I have 28 gauge in there. Since there's two coils, I up the wattage of my Sigeli to 34 watts. I know around 17 watts is going to each coil, which is fine for me. If I use a thicker gauge wire, I know that 17 watts won't heat it up very fast, so I usually up the wattage.
I really don't think about it that much, I just have a general rough idea on where the power should be based on the thickness of the wire.
When I go mechanical, I do have some 24 gauge I play around with. I like to use a fairly high (for me) wattage... I like around 30 watts. I punch in 4.2 volts in ohms law calculator, and 30 watts, and it tells me to use a .558 ohm setup... So, I aim for two .6 ohm coils using 24 gauge to end up with a .3 ohm dripper setup. I double check the safety by punching in the end result in the calculator. .3 ohm setup at 4.2 volts.. that uses 14 amps. I only use VTC 4's, and that is well within the limits of the battery.
If I wanted to use 26 gauge, I know my 20 watts is my goal. That's .882 ohms in the calculator, so I aim for two .882 ohm coils using 26 gauge. That's tootie puffer area. I generally like it to run a tad bit more power for two coils, so I would aim for around a .7 ohm setup, which means two 1.4 ohm coils. I missed on the build I have now, and made two 1.2 ohm coils, which means it's a .6 ohm setup. Since I use it on my Sigeli, I can change the wattage to compensate.... currently, I have it set for 37 watts, which is close enough. The sigeli only has a reading to tens, so I am guessing it's a bit higher ohms than just .6.
Does that make any sense to you? It kind of gives you an idea of how I go about my building strategies. It really goes faster than what it takes to type it. it gets to the point when I say... I want a hotter vape, so I'll use 26 gauge, let's aim for .7 or .8ish. I think I confused myself when typing this, but I did all this thinking a while back ago, and haven't had to second guess it since.
Okay, I think I understand now, but just to clarify, the amps being drawn remain the same? I'm using a cool fire 4 right now, with 1 .9 ohm coil at 25 watts, the battery is max 12 amps, if I make two 1.6 ohm coils which will give me a .8 resistance running it at 25 watts, will it still only draw 5.59 amps? I'm using a vape calculator on my phone that's giving me these numbers lol.
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