Question about vape time.

[MisterMike]

Hey everyone,

I just did a whole bunch of convoluted calculations figuring out current, continuous load time and draws per battery charge trying to figure out roughly how long my battery would last with a 2.0ohm carto versus a 2.5ohm atomizer, and came up with approximately 80% vape time for the lower resistance. Then I suddenly realized that 2.0 is 80% of 2.5.

(Yeah, I tend to do things the hard way, first time 'round.)

Given that the only variable here is resistance, is comparing the two resistances a good quick 'n' dirty method of comparing approximate vape times?

PS - Please let me know if I'm not making sense.

 

[HowlingBadger]

I'm no electrician (or mathematician for that matter) but yeah, I'd say it is. Seeing as like you said, the only variable of any importance is the resistance, you're probably safe to simply compare the ohm rating for a rough estimate of your battery life.

 

[Hitmetwice]

That makes "perfect" sense....glad you are on our side MisterMike.

 

[DemonCleaner]

Maybe try a sudoku or word scramble if you're bored. Angry birds is pretty fun.

 

[DaveP]

The standard answer is an hour for every 100mah capacity of the battery you use of vaping. It works out that way, plus or minus, it you use a middle range atomizer of 2 to 3 ohms. Below 2 ohms it drops drastically.

Also, unless you are using a boost regulator that maintains the output voltage as the battery decreases in voltage, you get to the point where you swap batteries before they flash and cut off. That makes it hard to calculate a "good" vape time from the mah capacity of a battery.

Inside that, you can pull lower amps at roughly the same wattage by using a 3 ohm coil at a higher voltage. You would think that a watt is a watt, but we all know that an appliance cost less to run at 220v than at 110v. Freezers and air conditioners are a good example.

A 3 ohm carto pulls 1.4 amps and produces 5.88 watts of heat at 4.2v.
A 2 ohm carto pulls 1.7 amps and produces 5.78 watts of heat at 3.4v.

The vape will be roughly the same, but the current load is significantly less while the wattage is fairly close. It's not a lot of difference, but it's interesting that the higher voltage draws lower mah from the battery.

The short answer is just swap batteries when the vape falls off and record the time.

 

[DemonCleaner]

The standard answer is an hour for every 100mah capacity of the battery you use of vaping. It works out that way, plus or minus, it you use a middle range atomizer of 2 to 3 ohms. Below 2 ohms it drops drastically.

Inside that, you can pull lower amps at roughly the same wattage by using a 3 ohm coil at a higher voltage. You would think that a watt is a watt, but we all know that an appliance cost less to run at 220v than at 100v. Freezers and air conditioners are a good example.

A 3 ohm carto pulls 1.4 amps and produces 5.88 watts of heat at 4.2v.
A 2 ohm carto pulls 1.7 amps and produces 5.78 watts of heat at 3.4v.

The vape will be about the same, but the current load is significantly less while the wattage is fairly close. It's not a lot of difference, but it's interesting that the higher voltage draws lower mah from the battery.

You must be one of those musicians who knows which hole to plug into on the back of the amp...I'm still working on that one.

 

[ChellyNelly]

Maybe try a sudoku or word scramble if you're bored. Angry birds is pretty fun.

You're so funny. I love your comments

 

[Concat]

Pretty much.

I = V / R

Now divide the mAh by I to get the approximate life of the charge. Of course it's never that simple, because the voltage isn't completely static.