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Test that setup with a multimeter. A dual coil will measure half the resistance of each individual coil. That is to say, if you wrap two 1Ω coils, and put them on a dual coil atomizer, you will end up with a resistance of 0.5Ω.
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I wrapped my igo-w with dual coils of 3/4 wraps 28 gauge. It came out as .5ohms on an eVic. So what exactly is the resistance of these coils, can they be used with a 18350(10c)? Im not sure if the resistance is .5 or 1ohm since its a dual coil. Thank you for answers
You've got two coils at 1 ohm each. The resistance the battery will see is 0.5 ohms because the battery is running them both so using twice the power one would need.
It's going to be drawing about 8 amps with a fresh battery. I'm not aware of any 18350 battery on the market that has a 10C rating, or one that can handle 8 amps.
What battery do you have?
Sorry I was mistaken, it's a 6c battery (aw imr
Technically I can just take out one coil and it will be 1ohm res to the batt right?
My fuse broke on my multimeter so I can't read resistance but still want to vape
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Yea, you can take out one coil and it will become a 1ohm build. perfectly fine for an AW IMR 18350. You can go to about .8ohm on the AW IMR 18350 and still be within its rated capacity. Any lower is not suggested for safe use.l
.65 is also fine on an 18350, so .7 is ok but as the poster above me said .8 is safe for sure.
To the OP, it sounds like you need to do more research. Put down the dual coils and do a bunch of reading.
To the OP, it sounds like you need to do more research. Put down the dual coils and do a bunch of reading.
I've done my reading. I know my amp limits (even though I made a mistake earlier) and I know how to build. But I was just confused on parallel resistance and how's it's read on an evic
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