Quick Question For Math Whiz

[MsGoddess2U]

I might be way off base here and its ok if you laugh...I feel like an idiot. I used to be so good with math but haven't really used it for years.

I have made some liquid that I believe needs more flavor. It tasted good on my test batch but my 30ml batch isn't as flavorful.

To get the exact amount for future reference, I would....measure what I have left, multiply that by the percentage of flavor used when I mixed it, to get the exact amount of flavor that is in remain liquid, subtract that from the remaining liquid value, then multiply the product of that operation by the percentage I want to increase it to, to find the exact amount of flavoring to add....is this correct?

 

[retired1]

Most of us just add a drop or two of flavoring to see if it improves.

 

[MsGoddess2U]

I know I'm new at this but I honestly don't see a drop or 2 making a difference in a 30ml bottle that's obviously too weak...

 

[dannyv45]

How are you measuring (By drop, %, ML). What are you using to measure (Dropper, syringe, flask, Pipette). How you measure and what you use makes all the difference in accuracy. The most accurate way to measure is to use a calculator such as the E-juice me up cal. And measure in ML's and percentages with syringes and measuring cylinders.


Get a good e-juice calculator here.
http://ejuice.breaktru.com/

 

[westhc]

I use excel when I want to modify %s of flavoring in a recipe. I measure in ml's and use a premixed pg/vg/nic base.
Here's an example for a single flavor recipe..

Base ml Flavor ml Total
A 10 ml @ 15 % 8.5 1.5 10
B 8 ml left @ 15% 6.8 1.2 8
C 10 ml @18% 8.2 1.8 18
D Add (D-C) 1.4 0.6 10

For multiple flavors just add additional columns for each flavor.

 

[bwh79]

....is this correct?

Sort of. It'll work, but it won't be exact. Let's try an example:

You mixed up a batch with 15% flavor. After tasting, you decide to try and up it to 20%. You have 11.5ml remaining. You want to add another 5% flavor, but you can't just work out 5% of 11.5ml (which, by the way is 0.575ml) because, after adding the flavor, you won't have 11.5ml anymore, but something slightly higher than that. You will also be affecting your nicotine level, diluting it slightly by adding nicotine-free flavoring. The simplest way to do it would be to mix up another 11.5ml, at the same nic level, but this time with 25% flavoring. Then mix the two together. The 15% and 25% flavors will average out to 20%, and since the nic levels were the same going in, they will be unaffected in the final mix.

If you don't want to make a whole 'nother batch, and just want to add flavor to your existing juice (and say to hell with the nic level, it won't be off by that much anyway), there's still a way to do it. Algebra time! This is the classic "solve for x" type of problem. The only trouble now, is figuring out the actual equation we are to solve. This is why we did all those word-problems, way back when:

"Ms. Goddess has 11.5ml of juice at 15% flavoring. How much flavoring should she add to her juice, so that the final mixture is 20% flavoring?"

You have 11.5ml of juice, 15% of which (1.725ml) is flavoring, and the remaining 85% (9.775ml) is "other." We want to add "x" amount of flavoring, so that "1.725 + x" is equal to 20% of "11.5 + x". Now, we have our equation:

1.725+x = 0.2*(11.5+x)

Multiply by 5 on both sides:
5*(1.725+x) = 11.5+x

Expand and simplify:
(5*1.725)+(5*x) = 11.5+x
8.625+5x = 11.5+x

Combine like terms:
8.625+4x = 11.5 <-- subtract x from both sides to get all the x's on one side.
4x = 2.875 <-- subtract 8.625 from both sides to get all the x's by themselves.

Divide both sides by 4:
x = 0.71875

You should add approx. 0.72ml of flavoring to your 11.5ml of juice. That will give you 12.22ml, of which 1.725+0.72=2.445ml is flavoring. 2.445/12.22 = 0.200081833(...) or about 20.008%. It's not exactly 20%, only because we're rounding to the nearest 1/100 of a ml and adding 0.72ml instead of 0.71875ml exactly. If your measuring equipment has gradations in the 0.00025ml range, then more power to ya!

 

[MsGoddess2U]

Sort of. It'll work, but it won't be exact. Let's try an example:

You mixed up a batch with 15% flavor. After tasting, you decide to try and up it to 20%. You have 11.5ml remaining. You want to add another 5% flavor, but you can't just work out 5% of 11.5ml (which, by the way is 0.575ml) because, after adding the flavor, you won't have 11.5ml anymore, but something slightly higher than that. You will also be affecting your nicotine level, diluting it slightly by adding nicotine-free flavoring. The simplest way to do it would be to mix up another 11.5ml, at the same nic level, but this time with 25% flavoring. Then mix the two together. The 15% and 25% flavors will average out to 20%, and since the nic levels were the same going in, they will be unaffected in the final mix.

If you don't want to make a whole 'nother batch, and just want to add flavor to your existing juice (and say to hell with the nic level, it won't be off by that much anyway), there's still a way to do it. Algebra time! This is the classic "solve for x" type of problem. The only trouble now, is figuring out the actual equation we are to solve. This is why we did all those word-problems, way back when:

"Ms. Goddess has 11.5ml of juice at 15% flavoring. How much flavoring should she add to her juice, so that the final mixture is 20% flavoring?"

You have 11.5ml of juice, 15% of which (1.725ml) is flavoring, and the remaining 85% (9.775ml) is "other." We want to add "x" amount of flavoring, so that "1.725 + x" is equal to 20% of "11.5 + x". Now, we have our equation:

1.725+x = 0.2*(11.5+x)

Multiply by 5 on both sides:
5*(1.725+x) = 11.5+x

Expand and simplify:
(5*1.725)+(5*x) = 11.5+x
8.625+5x = 11.5+x

Combine like terms:
8.625+4x = 11.5 <-- subtract x from both sides to get all the x's on one side.
4x = 2.875 <-- subtract 8.625 from both sides to get all the x's by themselves.

Divide both sides by 4:
x = 0.71875

You should add approx. 0.72ml of flavoring to your 11.5ml of juice. That will give you 12.22ml, of which 1.725+0.72=2.445ml is flavoring. 2.445/12.22 = 0.200081833(...) or about 20.008%. It's not exactly 20%, only because we're rounding to the nearest 1/100 of a ml and adding 0.72ml instead of 0.71875ml exactly. If your measuring equipment has gradations in the 0.00025ml range, then more power to ya!

Hahahaha!!! Yah...the nicotine level occurred to me while I was driving my daughter to an appointment. Thank you for pointing that out!!!!! Nic level is still important to me. I reduced accidentally and was very unhappy.

I have to do homework, then I'm gonna hit your math. I'm sure there's a calculator that does this but I need to brush up on my math anyways. THANK YOU!! I love math...I'm kinda excited to dive in to your examples