How many standard and highly variable "drops" of 100mg nicotine base would I add to a 15ml bottle of 0 to get 3mg 6mg 12mg 18mg. Thank you ladies and gentlemen, I am running out of scratch paper or quite frankly, I do not know the correct formula.
quick question for mathematicians
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15 mil X 3mg = 45/100 = .45
So .45 mil (just under 1/2 mil)
15 mil X 6mg = 90/100 = .90
So just under 1 mil
15 mil X 12mg = 180/100 = 1.8
So just under 2 mil
15 mil X 18mg = 270/100 = 2.7
So just over 2 1/2 mil or just under 3 mil
I advise against counting drops because every bottle is different and 100mg is strong stuff. My current bottle gets about 25 drops for 1 mil...but yours is probably different,
I hope I did all of that correctly...I'm not a mathematician..YMMV
So .45 mil (just under 1/2 mil)
15 mil X 6mg = 90/100 = .90
So just under 1 mil
15 mil X 12mg = 180/100 = 1.8
So just under 2 mil
15 mil X 18mg = 270/100 = 2.7
So just over 2 1/2 mil or just under 3 mil
I advise against counting drops because every bottle is different and 100mg is strong stuff. My current bottle gets about 25 drops for 1 mil...but yours is probably different,
I hope I did all of that correctly...I'm not a mathematician..YMMV
Remember this rule: c1v1=c2v2
c is concentration and v is volume. In this case you know c1 (100 mg/mL), c2 (3, 6, 12, 18 mg/mL), and v2 (15mL). You want to solve for v1 therefore the equation would be v1=(c2v2)/c1
Starting with the 18 mg you would have v1=(18mg/mL*15mL)/100 mg/mL. Solving, you would need 2.7 mL of 100mg/mL nicotine base diluted to 15 mL in "everything else". For 12 mg/mL you would need 1.8 mL, 6 mg/mL you need 0.9 mL, and 3 mg/mL you need 0.45 mL.
Water is approximately 20 drops/mL but that is a really inaccurate measurement. I would suggest running by the pharmacy and get some syringes in varying volumes. Be honest and tell the pharmacist what you're doing and they will be more than happy to help you.
c is concentration and v is volume. In this case you know c1 (100 mg/mL), c2 (3, 6, 12, 18 mg/mL), and v2 (15mL). You want to solve for v1 therefore the equation would be v1=(c2v2)/c1
Starting with the 18 mg you would have v1=(18mg/mL*15mL)/100 mg/mL. Solving, you would need 2.7 mL of 100mg/mL nicotine base diluted to 15 mL in "everything else". For 12 mg/mL you would need 1.8 mL, 6 mg/mL you need 0.9 mL, and 3 mg/mL you need 0.45 mL.
Water is approximately 20 drops/mL but that is a really inaccurate measurement. I would suggest running by the pharmacy and get some syringes in varying volumes. Be honest and tell the pharmacist what you're doing and they will be more than happy to help you.
A drop is not a standard, recognised measure of volume, so especially since you are using the highest concentration of nic liquid available for retail sale, you might consider using something like ml, or even some accurate weighing scales.
Given the variability of drops between different users and different bottles, your outcome is likely to vary too.
Invest in nic testing kits.
T
Given the variability of drops between different users and different bottles, your outcome is likely to vary too.
Invest in nic testing kits.
T
Not really tricky. But there is certain practical gear you need to do this both correctly and safely. At the most basic level that would be a handful of syringes.
Yes I have all the syringes I can handle, just thought someone would know off the off the top of their head how many standard and HIGHLY variable "drops" just to save me time on about 30 bottles of zero I have, I could vape a 4-9mg and be happy so the variation that would be acceptable to me would not be a concern. Why I made a batch of zero and bottle it, ill never know.
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