Are my theories correct or im still not getting it?
Thannks![]()
You're close, but not quite there.
Before I get to your specific questions, all of this stuff is governed by Ohm's Law, which is a math formula that kind of explains how this stuff works, and you'll need to understand it a little bit to make it all make sense. Basically, you're looking at 4 different pieces that all fit together to describe what's going on electrically.
Voltage (volts): This is the potential energy available to you. It covers how much power you have to work with.
Resistance (ohms): This is how difficult it is for the power to go through the atomizer. Resistance holds back the power. A good way to think about it is like waving your hand through the air, waving your hand through a tub of water, and waving your hand through a bucket of thick mud. With air, there's almost no resistance, but mud has a ton of it, so it's going to take more energy to move your hand at the same speed.
Current (amps): This is how much electricity is actually flowing through your atomizer, and it's determined by how much power you have (voltage) and how hard it is to go through the atomizer (resistance). This is also the most important number for battery safety - the higher the current, the more stress you're putting on the battery, and the less time you're going to get out of it.
Wattage (watts): For vapers, this number is like a summary of all the stuff above. It's the number we use to describe our vape most of the time. A 10 watt vape on one single coil is generally the same on another single coil, regardless of how many volts and ohms your setup is (there are a lot of other variables that play into your vapor production and flavor, but we're talking basics here for now, so I'm going to leave them out to avoid making it more complicated). This is also determined by how much power you have (volts) and how much resistance you have (ohms).
So as vapers, we need to be able to figure out two numbers from our setup: amps and watts. Amps is your voltage divided by your resistance, so a fresh 4.2 volt battery with a 1.5 ohm coil pulls (4.2 / 1.5 = 2.8) 2.8 amps. Watts is voltage squared divided by resistance, so that same setup is vaping at (4.2 x 4.2 / 1.5 = 17.74 / 1.5 = 11.76) 11.76 watts. If your voltage changes OR your resistance changes, so do the numbers. For example, if I have a variable voltage mod, and I set it at 5 volts with the same 1.5 ohm coil, now I'm vaping at 16.66 watts. I can also get that same 16.66 watt vape by putting a 1.06 ohm coil on the original 4.2 volt battery.
I know that's complicated, but understanding all this interplay makes it a lot easier to understand the answers to your questions. I'm going to get to those in the next post.
If you don't want to do the math yourself, there's a great Ohm's Law Calculator online.