Since I've started using a tank with my VV mod, it's of course easier to pay attention to how much liquid is being consumed. Yesterday, I was feeling a bit dissatisfied with what I was vaping and, for the first time in quite a while, hooked up the multimeter to check my voltage. I was somewhere around 4.0V and decided to crank it up to 5V. Much better. But it seemed like I went through that tank much more quickly than before. Not just 20% faster as I might have expected, but seemingly closer to twice as fast. This was obviously not a controlled experiment and it's entirely possible that I was dragging more greedily, owing to my increased enjoyment. But it led to a question: is the relationship between voltage and vaporization linear, or does the curve get steeper with an increase in voltage?
Voltage and consumption
- Thread starter PaulB
- Start date
- th_trl_thread_readers 0
- Status
Hi. It definitely gets steeper. The amount of vaporization you get is largely a function of the power being dissipated by the coil.
An equation for power: P = E²/R (voltage squared, divided by resistance)
So, if you were using a 2 ohm atty at 4v, then 4 * 4 / 2 = 8 watts of power.
If you then crank it to 5v, then 5 * 5 / 2 = 12.5 watts, or about 56% more power.
That's a significant difference.
An equation for power: P = E²/R (voltage squared, divided by resistance)
So, if you were using a 2 ohm atty at 4v, then 4 * 4 / 2 = 8 watts of power.
If you then crank it to 5v, then 5 * 5 / 2 = 12.5 watts, or about 56% more power.
That's a significant difference.
- Status
Similar threads
