Voltage Drop-the concept

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the_vape_nerd

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So I do a lot of reading here and I continually see the term "voltage drop". What I think it means is this....

A fresh-off-the-charger 18650 will be at 4.2v for example. When you stick that battery into a mod the mod itself will have some internal resistance like between the contact point of the battery and the 510 connection. The difference in the 4.2 you are getting off the battery and the actual voltage comnig out of the mod at the contact point is referred to as "voltage drop".

First can you tell me if this is correct, and secondly can you tell me how i'd go about measuring voltage at the 510 connection with a multimeter? i figure the positive lead goes into the connection itself but where does the ground lead go?

Finally, I need help with another term that some of you may laugh at but what does "under load" mean? does this mean like when you are actually firing the device as opposed to it just resting without the button pushed?
 

timk

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Voltage drop is the mod's resistance pulling the voltage down with the mod itself being the load. Think of the mod absorbing energy much like a coil would, but the rise in temp won't be noticeable. This is overly simplified because the "drop" is likely multiple points of extra and not needed resistance. Everything has resistance, choosing the materials that have the least resistance by molecular structure is one way to alleviate voltage drop. The other way is to improve connection points to reduce resistance.

The negative side would go on the threaded part of the 510 or anywhere that is making up the negative side of the circuit.

Under load means just that, when there is a load on the battery, measurements will be different. Firing a coil is a load to the battery. Different batteries are better at heavy loads than others. Load is measured in amps usually.
 
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